Answer: m = 50 g ZnSO4
Explanation: First is convert the moles of Zn to the moles of ZnSO4 by having their mole ratio which is 2:2 based from the balanced equation. Next is convert the moles of ZnSO4 to mass using its molar mass.
0.311 mole Zn x 2 moles ZnSO4 / 2 moles Zn
= 0.311 moles ZnSO4
0.311 moles ZnSO4 x 161 g ZnSO4 / 1 mole ZnSO4
= 50 ZnSO4
Answer:
- <em>Oxidation half-reaction</em>:
Fe²⁺(aq) → Fe³⁺(aq) + 1e⁻
- <em>Reduction half-reaction</em>:
Ce⁴⁺(aq) + 1e⁻ → Ce³⁺(aq)
Explanation:
The reaction that takes place is:
- Fe²⁺(aq) + Ce⁴⁺(aq) → Fe³⁺(aq) + Ce³⁺(aq)
The <em>oxidation half-reaction</em> is:
- Fe²⁺(aq) → Fe³⁺(aq) + 1e⁻
It is an oxidation because the oxidation state of Fe increases from 2+ to 3+.
The <em>reduction half-reaction</em> is:
- Ce⁴⁺(aq) + 1e⁻ → Ce³⁺(aq)
It is a reduction because the oxidation state of Ce decreases from 4+ to 3+.
Answer:
3
Explanation:
2x5 is 10 then 13-10 is 3
The answer is (3) 0.200 kJ
Hope I helped!
Answer:
= 160 mL
Explanation:
The equation for the reaction is;
Ca(OH)2 + 2HNO3 -----> Ca(NO3)2 + 2H2O
Moles of Ca(OH)2 = 0.080 L x 5.00^-3 M
= 0.0004 moles
From the reaction; 2 moles of HNO3 reacts with 1 mole of Ca(OH)2
Thus; moles of HNO3 = 0.0004 Moles × 2
= 0.0008 moles
Volume = moles/ molarity
Therefore; volume of HNO3= 0.0008 Moles/ 5 × 10^-3 M
<u>= 0.16 L or 160 mL</u>
