<span>1/2x+3y/4=5 => (1/2)x + (3/4)y = 5
1/5x+3y/2=2 => (1/5)x + (3/2)y = 2
Eliminate the fractional coefficients: Mult. the first equation by 4 and mult. the second equation by 10:
2x + 15y = 20
</span><span>Multiply the 1st equation by -1:
-</span>2x - 3y = -20
2x + 15y = 20
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12y = 0, so y = 0. Then the first equation becomes 2x + 3(0) = 20, or
x=10.
Solution is (10,0).
Answer: C. Infinite
Explanation: (To explain this answer, I'll use 1 = 1) When you get 1 = 1 after doing an equation, this mean the answer is "all real numbers", which is the same term as "infinite" because it will always be true. Therefore, 0 = 0 will always be a true statement.
g(x) = x^2 + 1(3x - 5)
<em><u>Replace all x's with 4.</u></em>
g(4) = 4^2 + 1(3 * 4 - 5)
g(4) = 16 + 1(12 - 5)
g(4) = 17(7)
g(4) = 119 (This is your answer.)
Answer: rotation then translation
Step-by-step explanation: