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Assoli18 [71]
3 years ago
15

What kinds of energy does the Sun provide earth

Chemistry
2 answers:
Whitepunk [10]3 years ago
7 0
The sun emits rays of heat and our solar panels take in that heat and transfer that heat into energy. Sun is also a way of keeping warm or thermal energy
Not going to explain how a solar panel transfers heat into electricity since that would take an entire college class period to explain.
AysviL [449]3 years ago
5 0
 I am positive it is solar energy
 

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5. A beam of photons with a minimum energy of 222 kJ/mol can eject electrons from a potassium surface. Estimate the range of wav
torisob [31]

Answer: The range of wavelengths of light that can be used to cause given phenomenon is 8.953 \times 10^{21} m.

Explanation:

Given: 222 kJ/mol (1 kJ = 1000 J) = 222000 J

Formula used is as follows.

E = \frac{hc}{\lambda}

where,

E = energy

h = Planck's constant = 6.625 \times 10^{-25} Js

c = speed of light = 3 \times 10^{8} m/s

Substitute the values into above formula as follows.

E = \frac{hc}{\lambda}\\222000 J = \frac{6.625  \times 10^{-34}Js \times 3 \times 10^{8} m/s}{\lambda}\\\lambda = 8.953 \times 10^{21} m

Thus, we can conclude that the range of wavelengths of light that can be used to cause given phenomenon is 8.953 \times 10^{21} m.

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3 years ago
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3 years ago
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lutik1710 [3]

If I’m right this should be the answer

7 0
3 years ago
If i have an 86 and i don’t do a 50 point assignment, what will my grade be in the class?
nexus9112 [7]
Well you are at a 86% so t<span>his is considered a "B" grade on an average grade scale. If you take 50 points we would need to know the Total point you could have got in that class to be able to see how much a percent was the assignment work and then take that percentage of the assignment and subtract it from the 86% to see where on the scale you would fall in after the assignment points were taken off.   Hope this helps :)
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3 years ago
The formula for lithium oxide is A) Li2O B) LiO2 C) LiO D) Li2O3
Greeley [361]
Li2O is the formula for <span> lithium oxide</span>
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