There are 1.93 x 10²⁴ particles
<h3>Further explanation</h3>
Given
3.2 moles of Neon gas
Required
Number of particles
Solution
The mole is the number of particles(molecules, atoms, ions) contained in a substance
<em>1 mol = 6.02.10²³ particles
</em>
Can be formulated
N=n x No
N = number of particles
n = mol
No = Avogadro's = 6.02.10²³
So the number of particles for 3.2 moles :
N = 3.2 x 6.02.10²³
N = 1.93 x 10²⁴
or
we can describe it using Avogadro's number conversion factor
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Answer:
Explanation:
CH₃COOH + NaOH = CH₃COONa + H₂O .
42.5 mL of .115 M of NaOH will contain .0425 x .115 moles of NaOH
= 48.875 x 10⁻⁴ moles NaOH
It will react with same number of moles of acetic acid
So number of moles of acetic acid in 3.45 mL = 48.875 x 10⁻⁴
number of moles of acetic acid in 1000 mL = 48.875 x 10⁻⁴ x 10³ / 3.45 moles
= 1.4167 moles
= 1.4167 x 60 gram
= 85 grams .
So 85 grams of acetic acid will be contained in one litre of acetic acid.
