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fiasKO [112]
3 years ago
15

A student measures the length and mass of an object records the link is 45.2 cm convert distance measurement to the correct SI b

ase unit
.4520
.452
4.52x10-4km
17.8in
Chemistry
1 answer:
VladimirAG [237]3 years ago
4 0

As per the International System of Units is a form of metric system in which distance is expressed in meters.

The given distance is 45.2 cm

Convert centimeter (cm) to SI base unit (meter)

One hundred centimeters is equivalent to one meter

I.e. 100 cm = 1 m

Therefore, the given distance of 45.2 cm =  

= 45.2 cm * 1 m/100 cm = 0.452 m

Thus, the correct SI base unit for 45.2 cm = 0.452 m

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Sodium tert-butoxide (NaOC(CH3)3) is classified as bulky and acts as Bronsted Lowry base in the reaction. It is reacted with 2-c
IceJOKER [234]

Answer:but-1-ene

Explanation:This is an E2 elimination reaction .

Kindly refer the attachment for complete reaction and products.

Sodium tert-butoxide is a bulky base and hence cannot approach the substrate 2-chlorobutane from the more substituted end and hence major product formed here would not be following zaitsev rule of elimination reaction.

Sodium tert-butoxide would approach from the less hindered side that is through the primary centre and hence would lead to the formation of 1-butene .The major product formed in this reaction would be 1-butene .

As the mechanism of the reaction is E-2 so it will be a concerted mechanism and as sodium tert-butoxide will start abstracting the primary hydrogen through the less hindered side simultaneously chlorine will start leaving. As the steric repulsion in this case is less hence the transition state is relatively stabilised and leads to the formation of a kinetic product 1-butene.

Kinetic product are formed when reactions are dependent upon rate and not on thermodynamical stability.

2-butene is more thermodynamically6 stable as compared to 1-butene  

The major product formed does not follow the zaitsev rule of forming a more substituted alkene as sodium tert-butoxide cannot approach to abstract the secondary proton due to steric hindrance.

5 0
3 years ago
Elements that have the following qualities: Lustrous, Solid at Room Temperatures, They react and form Basic Compounds, Great con
Tatiana [17]

Answer:

They are classified as METALS.

Explanation:

Elements are simple substances that cannot be chemically broken down into smaller substances. Based on different characteristics, they are classified into 3 namely:

- metals

- non metals and

- metalloid( mainly act as semi- conductor).

METALS are the type of elements that loses electrons to form positive ion, that is, they are electropositive elements. They are distinguished by the following characteristics:

- LUSTROUS: they have the ability to reflect light from its surface.

- At room temperature: Metals are solid are room temperature with the exception of Mercury which is liquid at room temperature.

- They react and form Basic Compounds

- Great conductor: most metals are great conductors of heat and electricity because they possess free electrons.

- Melting Point: they have high melting points.

8 0
3 years ago
Scientist can use trees to look at climates of the past. How? What information can they gather and how do they gather it? Explai
andrezito [222]

Explanation:

Scientist use trees a whole lot to look at climate of the past by examining tree rings.

These are layers of cambium in each successive years formed. They have an annual growth pattern and are known as tree rings.

Tree rings can be used to decipher the age of a tree.

  • These three rings can be used to interpret climatic patterns.
  • During a wet climate, the tree rings are more robust and bigger.
  • In a dry climate, the rings are thinner.
  • These alternating patterns can be used to decipher the climatic signatures in a tree.
  • Sometimes, it is possible to evaluate some certain isotopes that are useful in climatic studies.

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6 0
3 years ago
The freezing point of benzene is 5.5°C. What is the freezing point of a solution of 2.60 g of naphthalene (C10H8) in 675 g of be
Mrac [35]

<u>Answer:</u> The freezing point of solution is 5.35°C

<u>Explanation:</u>

The equation used to calculate depression in freezing point follows:

\Delta T_f=\text{Freezing point of pure solution}-\text{Freezing point of solution}

To calculate the depression in freezing point, we use the equation:

\Delta T_f=iK_fm

Or,

\text{Freezing point of pure solution}-\text{Freezing point of solution}=i\times K_f\times \frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ (in grams)}}

where,

Freezing point of pure solution = 5.5°C

i = Vant hoff factor = 1 (For non-electrolytes)

K_f = molal freezing point elevation constant = 4.90°C/m

m_{solute} = Given mass of solute (naphthalene) = 2.60 g

M_{solute} = Molar mass of solute (naphthalene) = 128.2 g/mol

W_{solvent} = Mass of solvent (benzene) = 675 g

Putting values in above equation, we get:

5.5-\text{Freezing point of solution}=1\times 4.90^oC/m\times \frac{2.60\times 1000}{128.2g/mol\times 675}\\\\\text{Freezing point of solution}=5.35^oC

Hence, the freezing point of solution is 5.35°C

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3 years ago
Describe a consequence of overpopulation of deer in the forest areas of the northeastern United States
muminat
If the deer population were to overpopulate then that would mean that there would not be enough room for other living things. Also, there would be less grass and plants because of the deer eating it all. Hope this helps!!!
4 0
3 years ago
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