Answer:

Explanation:
Molarity is found by dividing the moles of solute by liters of solution.

We are given grams of a compound and milliliters of solution, so we must make 2 conversions.
1. Gram to Moles
We must use the molar mass. First, use the Periodic Table to find the molar masses of the individual elements.
- C: 12.011 g/mol
- H: 1.008 g/mol
- O: 15.999 g/mol
Next, look at the formula and note the subscripts. This tells us the number of atoms in 1 molecule. We multiply the molar mass of each element by its subscript.
6(12.011)+12(1.008)+6(15.999)=180.156 g/mol
Use this number as a ratio.

Multiply by the given number of grams.

Flip the fraction and divide.


2. Milliliters to Liters
There are 1000 milliliters in 1 liter.

Multiply by 2500 mL.


3. Calculate Molarity
Finally, divide the moles by the liters.


The original measurement has 2 significant figures, so our answer must have the same. That is the hundredth place and the 3 tells us to leave the 7.

1 mole per liter is also equal to 1 M.

Explanation:
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Answer:
yes it gives some bad effect
Explanation:
Answer:
1.023 J / g°C
Explanation:
Mass, m = 37.9 g
Temperature increase (change) = 25.0°C
Heat = 969 J
Specific heat capacity , c= ?
The relationship between these quantities is given by the equation;
H = mcΔT
c = H / mΔT
c = 969 / (37.9 * 25)
c = 969 / 947.5 = 1.023 J / g°C
Answer:
Diatomic molecules consist of two atoms that are chemically bonded. The two atoms can be the same or different chemical elements. As for whether or not they are compounds, there is not technically an answer. This is because all compounds are molecules, but not all molecules are compounds. For example diatomic molecules that comprise the chemical compounds nitric acid, carbon monoxide, and hydrogen chloride are made up of two different elements. As you can see, most diatomic molecules are not made up of the same kind of elements and not every diatomic molecule comprises a chemical compound.
hope this helps :)
Explanation: