2) carbon and hydrogen only.
Answer:
0.153M
Explanation:
57.3/97.994 (molar mass)=0.585 moles of H3PO4
.0585/3.820L=0.153M
Answer:
474.3 cm³
Explanation:
Given data:
Initial volume of chlorine gas = 568 cm³
Initial temperature = 25°C
Final volume = ?
Final temperature = -25°C
Solution:
Initial temperature = 25°C (25+273 = 297 K)
Final temperature = -25°C (-25 +273 = 248 K)
The given problem will be solve through the Charles Law.
According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.
Mathematical expression:
V₁/T₁ = V₂/T₂
V₁ = Initial volume
T₁ = Initial temperature
V₂ = Final volume
T₂ = Final temperature
Now we will put the values in formula.
V₁/T₁ = V₂/T₂
V₂ = V₁T₂/T₁
V₂ = 568 cm³ × 248 K /297 K
V₂ = 140864 cm³.K / 297 K
V₂ = 474.3 cm³
1) moles = mass/mR
CaCO3 Mr = 40 + 12 + (16×3)
= 52 + 48
= 100
mass = 15
so the moles would be 15 ÷ 100
which is 0.15 moles of CaCO3
2) moles = mass ÷ Mr
Mr of Al2O3 = 27 + (16×3)
= 27 + 48
= 75
mass = 204
so the moles would be 204/75 which is 2.72 moles of Al2O3
Explanation:
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