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Kipish [7]
3 years ago
15

Consider the following multistep reaction: A+B→AB(slow) A+AB→A2B(fast)−−−−−−−−−−−−−−−−− 2A+B→A2B(overall) Based on this mechanis

m, determine the rate law for the overall reaction.
Chemistry
1 answer:
Grace [21]3 years ago
8 0

Answer:

r = k × [A] × [B]

Explanation:

To determine the rate law, we simply use the slow step reaction equation. The slow step is the rate determining step in the reaction.

A+B→AB

And as we know, the rate of the reaction is proportional directly to the product of the concentration of the reactants which concentration is changing over the course of the reaction.

r = k × [A] × [B]

Where r = rate of reaction

k = reaction rate constant

[A] = Concentration of molecule A

[B] = Concentration of molecule B

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The line notation, Pt
mote1985 [20]

Answer:

copper metal is a product of the cell reaction.

Explanation:

In writing the line notation of a cell reaction, we ought to recall that the anode is placed at the left hand side of the notation while the cathode is placed at the right hand side of the notation.

If we look at the line notation shown in the question, we will realize that the Cu2+ (aq) | Cu(s) half cell is the cathode and that copper metal is the product of the reaction as shown by the notation.

3 0
3 years ago
What entropy change is associated with the reversible phase change from 1.0kg of ice to water at 0 ° C?
avanturin [10]

Answer:

1200 J/K  

Explanation:

The formula for the entropy associated with a reversible phase change is

\Delta S= \dfrac{q_{\text{rev}}}{T}

1. Calculate q

For a reversible phase change like melting,

q_{\text{rev}} = m\Delta_{\text{fus}}H = \text{1000 g} \times \dfrac{\text{334 J}}{\text{1 g}} = \text{334 000 J}

2. Calculate ΔS

\Delta S = \dfrac{q_{\text{rev}}}{T} =\dfrac{\text{334 000 J}}{\text{273.15 K}} = \textbf{1200 J/K}

3 0
3 years ago
Help pls hehe
QveST [7]

Answer:

can't see clearly , post a clearer pic if possible

3 0
3 years ago
If 5.0 grams of sucrose, C12H22O11, are dissolved in 10.0 grams of water, what will be the boiling point of the resulting soluti
GaryK [48]

Answer : The boiling point of the resulting solution is, 100.6^oC

Explanation :

Formula used for Elevation in boiling point :

\Delta T_b=i\times k_b\times m

or,

T_b-T^o_b=i\times k_b\times \frac{w_2\times 1000}{M_2\times w_1}

where,

T_b = boiling point of solution = ?

T^o_b = boiling point of water = 100^oC

k_b = boiling point constant  = 0.52^oC/m

m = molality

i = Van't Hoff factor = 1 (for non-electrolyte)

w_2 = mass of solute (sucrose) = 5.0 g

w_1 = mass of solvent (water) = 10.0 g

M_2 = molar mass of solute (sucrose) = 342.3 g/mol

Now put all the given values in the above formula, we get:

(T_b-100)^oC=1\times (0.52^oC/m)\times \frac{(5.0g)\times 1000}{342.3\times (10.0g)}

T_b=100.6^oC

Therefore, the boiling point of the resulting solution is, 100.6^oC

5 0
3 years ago
What type of bonding occurs in a sample of pure copper, Cu? In other words, how is one copper atom held to another copper atom?
Aleonysh [2.5K]

B. metallic because copper is a metal

5 0
3 years ago
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