Answer:
- Option <u><em>C) The rates of the forward and reverse reactions are equal.</em></u>
Explanation:
NO₂ and N₂O₄ undergo the following <em>equilibrium</em> reaction:
That is a reversible reaction, i.e. there are two simultaneous reactions: the direct or forward reaction and the reverse reaction:
- Direct reaction: 2NO₂(g) → N₂O₄(g)
- Reverse reaction: 2NO₂(g) ← N₂O₄(g)
At the beginning, only NO₂(g) is in the sealed container. The NO₂ concentration is maximum, and the rate of the forward reaction is maximum.
As the reaction progresses, the concentration of NO₂ diminishes, and, consequently, the rate of the forward reaction decreases.
As soon as the N₂O₄ appears, the reverse reaction starts. At the beginning the rate is low, but as the N₂O₄ concentration increases the rate of the reverse reaction increases.
When both forward and reverse rates become equal the equilibrium has been reached. This is what is called a dynamical equilibrium.
Then, as per the choices, you have that, at equilibrium:
<u>A) No N₂O₄ is present</u>:
- False: as explained above, at equilibrium both NO₂ and N₂O₄ are present.
<u>B) No chemical reactions are occurring</u>.
- False: as explained above, at equilibrium both forward and reverse reaction are occurring at the same rate.
<u>C) The rates of the forward and reverse reactions are equal</u>.
- True: as explained, this is the meaning of dynamic equilibrium.
<u>D) The maximum number of molecules has been reached</u>.
- False: the number of molecules of each compound at equilibrium will be given by the constant of equiibrium, Keq = [N₂O₄] / [NO₂]², and this value varies with the temperature.
This is called bond energy, or bond enthalpy, and is measured in units of kilojoules per mole (kJ/mol).
He answer is 42 because you carry the one
Answer:
The three statements are true
Explanation:
For the reaction:
I₂O₅(s) + 5CO(g) → I₂(s) + 5CO₂(g)
State oxidation of iodine in I₂O₅ is:
5 O²⁻ = 10⁻
As you have 2 I and the molecule has no charge, <em>oxidation state of I is +5</em>.
The carbon in CO has an oxidation state of +2 and in CO₂ is +4. That means <em>the carbon is oxidized</em>
<em />
An oxidizing agent is a substance that produce the oxidation of the agent that reacts with this one. CO is oxidized because of I₂O₅ is producing its oxidation being <em>the oxidizing agent</em>
<em></em>
Thus,<em> the three statements are true</em>.
