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Kipish [7]
3 years ago
15

Consider the following multistep reaction: A+B→AB(slow) A+AB→A2B(fast)−−−−−−−−−−−−−−−−− 2A+B→A2B(overall) Based on this mechanis

m, determine the rate law for the overall reaction.
Chemistry
1 answer:
Grace [21]3 years ago
8 0

Answer:

r = k × [A] × [B]

Explanation:

To determine the rate law, we simply use the slow step reaction equation. The slow step is the rate determining step in the reaction.

A+B→AB

And as we know, the rate of the reaction is proportional directly to the product of the concentration of the reactants which concentration is changing over the course of the reaction.

r = k × [A] × [B]

Where r = rate of reaction

k = reaction rate constant

[A] = Concentration of molecule A

[B] = Concentration of molecule B

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The answer is option number one
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3 years ago
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mixture of N 2 And H2 Gases weighs 13.22 g and occupies a volume of 24.62 L at 300 K and 1.00 atm.Calculate the mass percent of
anygoal [31]

<u>Answer:</u> The mass percent of nitrogen gas and hydrogen gas is 91.41 % and 8.59 % respectively.

<u>Explanation:</u>

To calculate the number of moles, we use the equation given by ideal gas equation:

PV = nRT

where,

P = Pressure of the gaseous mixture = 1.00 atm

V = Volume of the gaseous mixture = 24.62 L

n = number of moles of the gaseous mixture = ?

R = Gas constant = 0.0821\text{ L atm }mol^{-1}K^{-1}

T = Temperature of the gaseous mixture = 300 K

Putting values in above equation, we get:

1.00atm\times 24.62L=n_{mix}\times 0.0821\text{ L atm }mol^{-1}K^{-1}\times 300K\\\\n_{mix}=\frac{1.00\times 24.62}{0.0821\times 300}=0.9996mol

We are given:

Total mass of the mixture = 13.22 grams

Let the mass of nitrogen gas be 'x' grams and that of hydrogen gas be '(13.22 - x)' grams

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

<u>For nitrogen gas:</u>

Molar mass of nitrogen gas = 28 g/mol

\text{Moles of nitrogen gas}=\frac{x}{28}mol

<u>For hydrogen gas:</u>

Molar mass of hydrogen gas = 2 g/mol

\text{Moles of hydrogen gas}=\frac{(13.22-x)}{2}mol

Equating the moles of the individual gases to the moles of mixture:

0.9996=\frac{x}{28}+\frac{(13.22-x)}{2}\\\\x=12.084g

To calculate the mass percentage of substance in mixture we use the equation:

\text{Mass percent of substance}=\frac{\text{Mass of substance}}{\text{Mass of mixture}}\times 100

Mass of the mixture = 13.22 g

  • <u>For nitrogen gas:</u>

Mass of nitrogen gas = x = 12.084 g

Putting values in above equation, we get:

\text{Mass percent of nitrogen gas}=\frac{12.084g}{13.22g}\times 100=91.41\%

  • <u>For hydrogen gas:</u>

Mass of hydrogen gas = (13.22 - x) = (13.22 - 12.084) g = 1.136 g

Putting values in above equation, we get:

\text{Mass percent of hydrogen gas}=\frac{1.136g}{13.22g}\times 100=8.59\%

Hence, the mass percent of nitrogen gas and hydrogen gas is 91.41 % and 8.59 % respectively.

5 0
3 years ago
Determine the volume at STP of 36.8 g of nitrogen dioxide(NO2)
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Answer:

17.92L

Explanation:

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3 years ago
Which of the following is a negative consequence of the application of scientific knowledge?
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A. Industrial pollution, the rest are considered positive
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If the dehydration reaction of an alcohol is successful. What changes would be seen in the ir spectrum for the product compared
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If the dehydration reaction of an alcohol is successful. The changes would be seen in the IR spectrum for the product compared to the starting material are as,

  • The O-H and  C-O  band is disappear from stating material
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In dehydration reaction of alcohol (  O-H and  C-O bond ) contain , the water molecule ( H_{2}O ) is release from the reactant and C-C double bond is form which is known as alkene in the product .

The reactant and product have different structure. To determine the structure of the compound IR spectroscopy is used. In IR spectrum the peak corresponds to 3400-3600 cm is missing in the product of  dehydration reaction of an alcohol. It means  O-H band is disappear from stating material.

learn about IR SPECTRUM

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