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Kipish [7]
3 years ago
15

Consider the following multistep reaction: A+B→AB(slow) A+AB→A2B(fast)−−−−−−−−−−−−−−−−− 2A+B→A2B(overall) Based on this mechanis

m, determine the rate law for the overall reaction.
Chemistry
1 answer:
Grace [21]3 years ago
8 0

Answer:

r = k × [A] × [B]

Explanation:

To determine the rate law, we simply use the slow step reaction equation. The slow step is the rate determining step in the reaction.

A+B→AB

And as we know, the rate of the reaction is proportional directly to the product of the concentration of the reactants which concentration is changing over the course of the reaction.

r = k × [A] × [B]

Where r = rate of reaction

k = reaction rate constant

[A] = Concentration of molecule A

[B] = Concentration of molecule B

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Come up with 2 examples of each law motion below: <br><br> 1st law:<br> 2nd law:<br> 3rd law:
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Tell me what acid-base properties can determine if a household chemical is an acid, base, or neutral substance.
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3 0
3 years ago
How much heat will be absorbed by a 26.3 g piece of aluminum (specific heat = 0.930 J/g・°C) as it changes temperature from 23.0°
kotykmax [81]

Answer:

\boxed {\boxed {\sf 1076.196 \ Joules}}

Explanation:

Since we are given the mass, specific heat, and temperature, we should use the following formula for heat energy.

q=mc\Delta T

The mass of the aluminum is 26.3 grams. Its specific heat is 0.930 Joules per gram degree Celsius. We need to find the change in temperature.

  • The change in temperature is the difference between the initial temperature to the final temperature.
  • The temperature changes <em>from</em> 23.0°C <em>to</em> 67.0°C, so the initial is 23 degrees and the final is 67 degrees.
  • ΔT= final temperature - initial temperature
  • ΔT= 67°C - 23°C
  • ΔT= 44°C

Now we know all the values.

  • m= 26.3 g
  • c= 0.930 J/g °C
  • ΔT= 44°C

Substitute the values into the formula.

q= (26.3 \ g}) \times (0.930 \ J/g \textdegree C) \times (44 \textdegree C)

Multiply the first two numbers together. The units of grams cancel.

q= 24.459 \ J/ \textdegree C \times 44 \textdegree C

Multiply again. This time, the units of degrees Celsius cancel.

q=1076.196 \ J

<u>1076.196 Joules</u> of heat will be absorbed by the piece of aluminum.

4 0
3 years ago
&gt; Exam Guidelines
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Answer:

A should be the correct answer I'm not sure but goodluck

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