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Artemon [7]
2 years ago
15

ANSWER ASAP REALLY NEED IT RN

Chemistry
1 answer:
Softa [21]2 years ago
4 0

Answer:

1. b

2. a

3. d

4. d

Explanation:

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Water molecules are composed of _________
Nataly [62]
Everything is made of atoms. An atom is the smallest particle of an element, like oxygen or hydrogen. Atoms join together to form molecules. A water molecule has three atoms: two hydrogen (H) atoms and one oxygen (O) atom.
5 0
3 years ago
The chemical formula for beryllium oxide is BeO.A chemist determined by measurements that 0.045 moles of beryllium participated
blondinia [14]

Answer: 0.405g

Explanation:

Molar Mass of Be = 9g/mol

Number of mole of Be = 0.045mol

Mass conc. Of Be = 0.045 x 9 = 0.405g

8 0
3 years ago
The carbon dioxide gas that was generated during this reaction was collected at 295K and 125 kPa. If 43.2 L of carbon dioxidegas
Vladimir [108]

Answer:

The balanced equation for this reaction is C2H2 + 502 + 4H2O + 3C02. What volume of carbon dioxide is produced when 2.8 L of oxygen are consumed? 25Explanation:

8 0
2 years ago
What volume of a 2.5 M NaOH solution is required to make 1 liter of a 0.75 M NaOH
defon
V1M1 = V2M2 

<span>V1 × 2.5 = 1 × 0.75,
so     V1 = 0.75/2.5
              = 0.3 </span>
6 0
3 years ago
The maximum amounts of lead and copper allowed in drinking water are 0.015 mg/kg for lead and 1.3 mg/kg for copper. Tell the max
GuDViN [60]

Answer:

  • <em>The maximum amount of copper allowed in 100 g of water is </em><u><em>0.00013 g</em></u>

Explanation:

To find the maximum amount of copper (in grams) allowed in 100 g of water use the maximum amount ratio (1.3 mg / kg)  and set a proportion with the unknown amount of copper (x) and the amount of water (100 g):

First, convert 100 g of water to kg: 100 g × 1 kg / 1000 g = 0.1 kg.

Now, set the proportion:

  • 1.3 mg Cu / 1 Kg H₂O = x / 0.1 kg H₂O

Solve for x:

  • x = 0.1 kg H₂O × 1.3 mg Cu / 1 kg H₂O = 0.13 mg Cu

Convert mg to grams:

  • 0.13 mg × 1 g / 1,000 mg = 0.00013 g

Answer: 0.00013 g of copper.

6 0
2 years ago
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