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3 years ago

What type of atmospheric conditions does weather describes

Chemistry

1 answer:

Alex3 years ago

4 0

Answer:

humidity, air temperature and pressure, wind speed and direction, cloud cover and type, and the amount and form of precipitation,

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The frequency of an x-ray wave is 3.0 x 1012MHz. Its wave speed is 3.0x 108m/s. Calculate the wavelength of the x-ray wave below

jasenka [17]

Answer: The wavelength of the x-ray wave is $10^{-10}m$

Explanation:

To calculate the wavelength of light, we use the equation:

$\lambda=\frac{c}{\nu}$

where,

$\lambda$ = wavelength of the light = ?

c = speed of x-ray= $3.0\times 10^8m/s$

$\nu$ = frequency of x-ray = $3.0\times 10^{12}MHz=3.0\times 10^{18}Hz= 3.0\times 10^{18}s^{-1}$ $(1Hz=1s^{-1})$

Putting in the values:

$\lambda=\frac{3.0\times 10^8m/s}{3.0\times 10^{18}s^{-1}}=10^{-10}m$

Thus the wavelength of the x-ray wave is $10^{-10}m$

5 0

3 years ago

Why a dipole develops in a molecule

Debora [2.8K]

Explanation:

When the covalent bonds in a molecule are polarized so that one portion of the molecule experiences a positive charge and the other portion of the molecule experiences a negative charge. This separation of opposite charges creates an electric dipole.

7 0

3 years ago

Read 2 more answers

Describe the results of a physical change and list<br> three examples of physical change.

Alex Ar [27]

Physical changes are changes affecting the form of a chemical substance, but not its chemical composition. Physical changes are used to separate mixtures into their component compounds, but can not usually be used to separate compounds into chemical elements or simpler compounds.

Ex: cutting a paper, gaining weight, cutting hair

8 0

3 years ago

How does acid affect limestone?

Andrej [43]

Answer:

It reacts by fizzing and wearing away/dissolving the rock.

Explanation:

7 0

3 years ago

Ten pints of 15 % salt solution are mixed with 15 pints of 10 % salt solution. What is the

sergij07 [2.7K]

$Concentration\ rate=\frac{mass\ of\ product}{mass\ of\ substance}*100\%\\\\
15\%=\frac{m_1}{ms_1}*100\%\\ms_1=10pints\\
15\%=\frac{m_1}{10}*100\%\\
\frac{15}{100}=\frac{m_1}{10}\ \ |*10\\
m_1=\frac{150}{100}=1,5pints\\\\
10\%=\frac{m_2}{15}*100\%\\
0,1=\frac{m_2}{15}\ \ |*15\\
1,5=m_2\\
Resulting\ solution:\\
ms=ms_1+ms_2=15+10=25pints\\m=m_1+m_2=1,5+1,5=3pints
\\\frac{m}{ms}*100\%=\frac{3}{25}*100\%=12\%$

7 0

3 years ago