Answer:
No, the car will not make it to the top of the hill.
Explanation:
Let ΔX be how long the slope of the hill is, Δx be how far the car will travel along the slope of the hill, Ф be the angle the slope of the hill makes with the horizontal(bottom of the hill), ki be the kinetic energy of the car at the bottom of the hill and vi be the velocity of the car at the bottom of the hill and kf be the kinetic energy of the car when it stop moving at vf.
Since Ф is the angle between the horizontal and the slope, the relationship between the angle and the slope and the height of the hill is given by
sinФ = 12/ΔX
Which gives you the slope as
ΔX = 12/sinФ
Therefore for the car to reach the top of the hill it will have to travel ΔX.
Ignoring friction the total work done is given by
W = ΔK
W = (kf - ki)
Since the car will come to a stop, kf = 0 J
W = -ki
m×g×sinФ×Δx = 1/2×m×vi^2
(9.8)×sinФ×Δx = 1/2×(10)^2
sinФΔx = 5.1
Δx = 5.1/sinФ
ΔX>>Δx Ф ∈ (0° , 90°)
(Note that the maximum angle Ф is 90° because the slope of a hill can never be greater ≥ 90° because that would then mean the car cannot travel uphill.)
Since the car can never travel the distance of the slope, it can never make it to the top of the hill.
Answer: High voltage transmission minimizes energy losses during electricity transmission.
Explanation:
When electricity is to be transmitted over a long distance, high voltage transmission is preferred to minimize energy losses due to heat.
The higher the transmission voltage, the lower the current and the lesser the resitance in the wire and the lesser the energy lost due to heat during transmission.
High voltage transmission in kilowatts enables light weight cables to be used for long distance electricity transmission.
This explains why, even though only 110 V may be required at home by some appliances, but electricity is transmitted in kilovolts and often require a stepdown transformer
The answer is A) electric current ⚡️
Can i have brainliest
Answer:
the average net force on the truck is 3744 N.
Explanation:
Given;
mass of the truck, m = 1200 kg
initial velocity of the truck, u = 25 m/s
final velocity of the truck, v = 53 m/s
distance traveled by the truck, d = 350 m
The acceleration of the truck is calculated as;
v² = u² + 2ad
53² = 25² + (2 x 350)a
700a = 53² - 25²
700a = 2184
a = 2184 / 700
a = 3.12 m/s²
The average net force on the truck is calculated as;
F = ma
F = 1200 x 3.12
F = 3744 N
Therefore, the average net force on the truck is 3744 N.
I believe A is the correct answer!!