A galvanometer can be calibrated to read electric A) current B) Voltage C) either of these D) neither of these
1 answer:
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Answer:
the energy increases 4 times
Explanation:
A spring has an elastic potential energy that is given by the expression
K_e = ½ K (x-x₀)²
where x is the distance from the equilibrium point and k is the return constant
if the spring is stretched at x-x₀ = 2x₀, the energy value
K_e = ½ k (2x₀)²
K_e = ½ k 4 x₀²
K_e = 4 (½ k x₀²)
= 4
therefore the energy increases 4 times