Assume the snow is uniform, and horizontal.
Given:
coefficient of kinetic friction = 0.10 = muK
weight of sled = 48 N
weight of rider = 660 N
normal force on of sled with rider = 48+660 N = 708 N = N
Force required to maintain a uniform speed
= coefficient of kinetic friction * normal force
= muK * N
= 0.10 * 708 N
=70.8 N
Note: it takes more than 70.8 N to start the sled in motion, because static friction is in general greater than kinetic friction.
Since the current is inversely propotional to its resistance, when the voltage is doubled the current will be one-half
Answer:
11.6532 x 10⁻¹¹ J or 7.3 MeV is given off
Explanation:
Mass of an alpha particle = 4.0026u, ∴ mass of three = 12.0078u
Find the difference in mass.
Mass of three alpha - Mass of Carbon nucleus
12.0078u - 12u = 0.0078u
Since 1u = 1.66 x 10⁻²⁷ kg
Therefore, 0.0078u = 1.2948 x 10⁻²⁷
Now that we know Mass(m) = 1.2948 x 10⁻²⁷ and Speed (c) 3 x 10⁸ m²s⁻²
Formular for Energy ==> E₀ = mc²
E = (1.2948 x 10⁻²⁷) (3 x 10⁸ m²s⁻²)²
E = (1.2948 x 10⁻²⁷) (9 x 10¹⁶) J
E = 11.6532 x 10⁻¹¹ J
Or, if you need your energy in MeV
1 MeV = 1.60x10⁻¹³ J
Just do the conversion by dividing 11.6532 x 10⁻¹¹ J by 1.60x10⁻¹³ J
It will give you 7.3 MeV
Answer:
0.132 m
Explanation:
= mass of the ion = 5.29 x 10⁻²⁷ kg
= magnitude of charge on singly charged ion = 1.6 x 10⁻¹⁹ C
= radius of circular path followed by singly charged ion
= speed of the ion = 1.13 x 10⁶ m/s
= magnitude of the magnetic field = 0.283 T
Radius of the circular path is given as
= 0.132 m
Answer :Force is exerted by the Earth on the rock is 280 N .
Given :
Mass of rock falling falling , m = 28 kg .
Acceleration due to gravity , 
.
We need to find the force exerted by the earth on the rock .
Let force exerted be F .
Now , we know by Newton's Law Of Motion .
F = ma .......( 1 )
Here , m is mass and a is acceleration in this case it is .
Putting all these value in equation( 1 ) we get ,
Therefore, this is the required solution .
