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2 years ago

During a blood transfusion a client develops chills and a headache. What is the priority nursing action?

1 answer:

6 0

During a blood transfusion, a client develops chills and a headache. . Stopping the transfusion at once is the priority nursing action.

Overview. Your blood is made up of liquids and solids. The liquid portion, called plasma, is made up of water, salts, and proteins. More than half of blood is plasma. The solid part of blood contains red blood cells, white blood cells, and platelets.

Blood is a special bodily fluid. It consists of four main components: plasma, red blood cells, white blood cells, and platelets. Blood has many functions, including Transporting oxygen and nutrients to the lungs and tissues. Formation of blood clots to prevent excessive blood loss. The main function of red blood cells is to carry oxygen from the lungs to the tissues of the body. It then transports carbon dioxide out of the tissues as a waste product and back to the lungs. Hemoglobin is an important protein in red blood cells that carries oxygen from the lungs to all parts of the body.

Learn more about blood here

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An astronaut stands by the rim of a crater on the Moon, where the acceleration of gravity is 1.62 m/s2 and there is no air. To d

Nesterboy [21]

Answer:

12.1 seconds

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity = 0

s = Displacement = 120 m

a = Acceleration due to gravity on Moon = 1.67 m/s²

Equation of motion

$v^2-u^2=2as\\\Rightarrow -u^2=2as-v^2\\\Rightarrow -u^2=2\times -1.67\times 120-0^2\\\Rightarrow u=\sqrt{2\times 1.67\times 120}\\\Rightarrow u=20.02\ m/s$

$v=u+at\\\Rightarrow t=\frac{v-u}{a}\\\Rightarrow t=\frac{0-20.2}{-1.67}\\\Rightarrow t=12.1\ s$

Time taken by the rock to hit the bottom of the crater is 12.1 seconds

5 0

4 years ago

Please help .. there could be more than one answer to this question.

erma4kov [3.2K]

A and b.............

6 0

4 years ago

If data is biased, the data is faulty. It might be partially correct , but it is not scientifically accurate.

saw5 [17]

Hi,
I think that’s true.

8 0

3 years ago

Read 2 more answers

After 20 seconds, a 200-kg object increases its velocity from 15 m/s to 40 m/s. Determine the impulse applied to the object. (Al

sleet_krkn [62]

Answer:

Imp_{1-2}=5000[kg*m/s]

Explanation:

In order to solve this problem, we must use the principle of conservation of momentum, which is defined as the product of mass by Velocity.

It must be defined that the impulse after the force is applied is equal to the momentum before the impulse applied on the body.

ΣPbefore = ΣPafter

P = momentum = m*v [kg*m/s]

In this way, we will construct the following equation.

$(m_{1}*v_{1})+ Imp_{1-2}=(m_{1}*v_{2})$

where:

m₁ = mass of the object = 200 [kg]

v₁ = velocity of the object before the impulse = 15 [m/s]

v₂ = velocity of the object after the impulse = 40 [m/s]

Now replacing:

$(200*15) + Imp_{1-2} = (200*40)\\Imp_{1-2}=5000[kg*m/s]$

7 0

3 years ago

A ray of light passes from air into carbon disulfide (n = 1.63) at an angle of 28.0 degrees to the normal. what is the refracted

Snezhnost [94]

We can solve the problem by using Snell's law, which states
$n_i \sin \theta_i = n_r \sin \theta_r$
where
$n_i$ is the refractive index of the first medium
$\theta_i$ is the angle of incidence
$n_r$ is the refractive index of the second medium
$\theta_r$ is the angle of refraction

In our problem, $n_i=1.00$ (refractive index of air), $\theta_i = 28.0^{\circ}$ and $n_r=1.63$ (refractive index of carbon disulfide), therefore we can re-arrange the previous equation to calculate the angle of refraction:
$\sin \theta_r = \frac{n_i}{n_r} \sin \theta_r = \frac{1.00}{1.63} \sin 28.0^{\circ} = 0.288$
From which we find
$\theta_r = \arcsin (0.288)=16.7^{\circ}$

6 0

3 years ago