Question

A 1200 kg truck accelerates from 25 m/s to 53 m/s over a distance of 350 m.

Answer 1

Answer:

the average net force on the truck is 3744 N.

Explanation:

Given;

mass of the truck, m = 1200 kg

initial velocity of the truck, u = 25 m/s

final velocity of the truck, v = 53 m/s

distance traveled by the truck, d = 350 m

The acceleration of the truck is calculated as;

v² = u² + 2ad

53² = 25² + (2 x 350)a

700a = 53² - 25²

700a = 2184

a = 2184 / 700

a = 3.12 m/s²

The average net force on the truck is calculated as;

F = ma

F = 1200 x 3.12

F = 3744 N

Therefore, the average net force on the truck is 3744 N.