Speed would such a block have if pushed horizontally 106 m along a frictionless track by such a laser is 0.127 m / s
First, it is necessary to find the radiation pressure on the surface. You will find it using the following formula:
P = P / (πr ^ 2) c
where P is the pressure and c is the speed of light in vacuum
P = 27 * 10 ^ 6 / π (0.2 / 2) ^ 2 * (3 * 10 ^ 8)
= 286.62× = 2866N / m ^ 2.
Then you must calculate the force (F) and the acceleration (a). This is done through the formulas:
F = P * (πr ^ 2)
F = 2866 * π * (0.2 / 2) ^ 2 = 0.089N
As, a = F / m
a = 0.089 / 104 = 0.00085m / s ^ 2
You can now calculate the speed.
V = √2ad
V = √2 *0.00085 * 106
V = 0.127 m / s
The complete question is: You've recently read about a chemical laser that generates a 20.0-cm-diameter, 27.0 MW laser beam. One day, after physics class, you start to wonder if you could use the radiation pressure from this laser beam to launch small payloads into orbit. To see if this might be feasible, you do a quick calculation of the acceleration of a 20.0-cm-diameter, 104 kg, perfectly absorbing block. What speed would such a block have if pushed horizontally 106 m along a frictionless track by such a laser? Express your answer with the appropriate units.
Hello!
A force of 5 N produces an acceleration of 2 m/s2 on the object. What is the mass of the object ?
Data:
F (force) = 5 N
m (mass) = ?
a (acceleration) = 2 m/s²
Solving:
Answer:
2.5 kg
_______________________________
I Hope this helps, greetings ... Dexteright02! =)
Answer:
Explanation:
The distance traveled by the sound wave between the beats of the wing is its wavelength, since it is defined as the distance traveled by a periodic disturbance that propagates in a cycle, is defined as:
Where v is the speed of sound and f the frequency of the wing beats
115.94g of O₂ are produced by 250g of Ca(ClO₃)₂
<u>Explanation:</u>
Ca(ClO₃)₂ -->CaCl₂ + 3O₂
One mole of calcium chlorate give three moles of oxygen.
Molar mass of calcium chlorate is
40+(35.5+16*3)*2 = 207g/mol
Molar mass of Oxygen = 32g
1 mole of calcium chlorate decomposes to form 3 moles of oxygen.
So,
207g of Ca(ClO₃)₂ produces 3 X 32g of O₂
250g of Ca(ClO₃)₂ will produce =
= 115.94g of O₂
Therefore, 115.94g of O₂ are produced by 250g of Ca(ClO₃)₂