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scoundrel [369]
3 years ago
9

a current of 3 amps flows through a lamp which is connected to a 24 volt battery calculate the lamps resistance​

Physics
1 answer:
Stels [109]3 years ago
6 0

Answer:

8

Explanation:

<em>V = voltage</em>

<em>I = current </em>

<em>R = resistance </em>

V = IR is the equation to find out the Voltage of an item so if we move around the equation so we are trying to resistance it would become R = V/I. So....

V = IR

R = V/I

R = 24/3

<u>R = 8</u>

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a balloon inflated in a room at 297k has a volume of 4.00 l. the balloon is then heated to a temperature of 331 k. what is the n
Naddika [18.5K]
V2 = 4.4579 L

Since pressure is constant, use Charle’s law.
Charles's law, a statement that the volume occupied by a fixed amount of gas is directly proportional to its absolute temperature, if the pressure remains constant.

V(olume) 1 = V(olume) 2
————— —————
T(emperature) 1 T(emperature)2

4.00 L = V2
———- ———
297 K 331 K

Cross multiply
(4.00 L x 331 K) = (297 K x V2)
Simplify
1324 L/K = 297 K x V2
Isolate V2 by dividing out 297 K
1324 L/K = V2
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297 K
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Round to significant digits if required
7 0
2 years ago
Solve the inequality. x/3 is greater than or equal to - 6. a. x ≥ –9 b. x ≥ 9 c. x ≥ –18 d. x ≤ –18
NISA [10]
To get x on its own, you times the 3 over to the other side so the 3 cancels out on the LHS. 

~ x greater than or equal to -18

(C)
6 0
3 years ago
A 200kg bucket of cement<br>​
ozzi

Answer:

Yes. A 200 kg bucket of cement = About 440.925 pounds of cements.

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7 0
3 years ago
You place a 55.0 kg box on a track that makes an angle of 28.0 degrees with the horizontal. The coefficient of static friction b
Radda [10]

Answer:

\theta=34 \textdegree

Explanation:

From the question we are told that:

Mass m=55kg

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Coefficient of static friction \alpha =0.680

Generally, the equation for Newtons second Law is mathematically given by

For

\sum_y=0

N=mgcos \theta

for

\sum_x=0

F_{s}=mgsin\theta

Where

F_{s}=\alpha*N\\\\F_{s}=\alpha*m*gcos \theta

F_{s}=0.68*55*9.8*cos 28

F_{s}=323.62N

Therefore

\alpha mgcos \theta=mg sin \theta

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\theta=34 \textdegree

6 0
3 years ago
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Experience: I lived through Andrew and Wilma

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