Answer: If Tara puts 4 pennies in for every one Sam does then after he puts in 10 she would of put 40.
She put in 40 pennies. Hope this helps ;)
because in each case, the selected column composes one<span>-tenth of the grid in total. The number of blocks is different, but the proportion of space filled is the same.</span>
Alright so these ratios have many different forms but the way I use to remember the trigonometric ratios is:
SOH
CAH
TOA
This means:
Sine --> Opposite/Hypotenuse
Cosine --> Adjacent/Hypotenuse
Tangent --> Oppositie/Adjacent
With that in mind, number 1:
Would be Sine, or C.
Number 2 would be, Cosine, or E.
And number 3 would be Tangent, or B.
Hope that was helpful.
Firstly, we'll fix the postions where the 
women will be. We have 
forms to do that. So, we'll obtain a row like:
The n+1 spaces represented by the underline positions will receive the men of the row. Then,
Since there is no women sitting together, we must write that 
. It guarantees that there is at least one man between two consecutive women. We'll do some substitutions:
The equation (i) can be rewritten as:
We obtained a linear problem of non-negative integer solutions in (ii). The number of solutions to this type of problem are known: ![\dfrac{[(n)+(m-n+1)]!}{(n)!(m-n+1)!}=\dfrac{(m+1)!}{n!(m-n+1)!}](https://tex.z-dn.net/?f=%5Cdfrac%7B%5B%28n%29%2B%28m-n%2B1%29%5D%21%7D%7B%28n%29%21%28m-n%2B1%29%21%7D%3D%5Cdfrac%7B%28m%2B1%29%21%7D%7Bn%21%28m-n%2B1%29%21%7D)
[I can write the proof if you want]
Now, we just have to calculate the number of forms to permute the men that are dispposed in the row: 
Multiplying all results:
12/3 is 4 breaks 12x60 is 720mins at most with 4x20= 80 = 720-80=640/ 60 means we have 10.67 hours left 550/10.67= 51.55 mph
