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viva [34]
3 years ago
6

Suppose y = 48 + 3(2n - 1) is an explicit representation of an arithmetic sequence for integer values n ≥ 1. Find the xth partia

l sum of the series, as a quadratic function, where x represents the term number.
Mathematics
2 answers:
PSYCHO15rus [73]3 years ago
6 0

Answer: 3x2 + 51x

Step-by-step explanation:

omeli [17]3 years ago
5 0
a_n=48+3(2n-1)

The formula of the sum of the arithmetic sequence:
S_n=\dfrac{a_1+a__n}{2}\cdot n
calculate:
a_1=48+3(2\cdot1-1)=48+3=51
substitute
S_n=\dfrac{51+48+3(2n-1)}{2}\cdot n=\dfrac{99+6n-3}{2}\cdot n=\dfrac{96+6n}{2}\cdot n=3n^2+48n
Your answer is:
\boxed{f(x)=3x^2+48x}

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Can someone help me with these please.
ELEN [110]

Answer: Barbara did not include a variable in the term 1.49, which must represents the number of bottles of iced tea she needs to sell.

Step-by-step explanation:

Let be "x" the number of bottle of water Barbara needs to sell and "y"  the number of bottle of iced tea she needs to sell.

She sells iced tea for $1.49 per bottle and water for $1.25 per bottle, so she can write the following equation in order to calculate the number of bottles she needs to sell to earn $100:

1.25x + 1.49y = 100

Since Barbara wrote this equation:

1.25x + 1.49 = 100

We can conclude that the error Barbara made in writing the equation was: She did not include a variable in the term 1.49, which must represents the number of bottles of iced tea she needs to sell.

8 0
3 years ago
Water freezes at 0 degrees Celsius. A student discovered that adding half a cup of salt to a gallon of water lowers its freezing
Artemon [7]

Answer:

-7°C

Step-by-step explanation:

Freezing point of water = 0°C

By adding salt, freezing point lowers by 7°C ;

The freezing point of salt water can be expressed as ;

Since temperature lowers :

Freezing point of salt water :

Freezing point of water - 7°C

0°C - 7°C

= - 7°C

4 0
3 years ago
A sample of tritium-3 decayed to 94.5% of its original amount after a year.
Zolol [24]
(a) If y(t) is the mass after t days and y(0) = A then y(t) = Ae^{kt}.

y(1) = Ae^k = 0.945A \implies e^k = 0.945 \implies k = \ln 0.945

\text{Then } Ae^{(\ln 0.945)t} = \frac{1}{2}A\ \Leftrightarrow\ \ln e^{(\ln 0.945)t} = \ln \frac{1}{2}\ \Leftrightarrow\  ( \ln 0.945) t = \ln \frac{1}{2} \Leftrightarrow \\ \\
t = - \frac{\ln 5}{\ln 0.945} \approx 12.25 \text{ years}

(b)
Ae^{(\ln 0.945) t} = 0.20 A \ \Leftrightarrow\ (\ln 0.945) t \ln \frac{1}{5}\ \implies \\ \\
t = - \frac{\ln 5}{\ln 0.945} \approx 28.45\text{ years}
3 0
3 years ago
Find the equation of the line that is parallel to the line x+3y=-15 that passes through the origin
Monica [59]
You would subtract x from each side. It would then be 3y=-x-15. Then you would divide all of the equation by 3. Your final answer would be y=-3x-5.
5 0
3 years ago
What is 5/12 divided by 3/8
asambeis [7]

Answer:

1 1/9

Step-by-step explanation:

put the problem into the calculator and divide. so simple

5 0
2 years ago
Read 2 more answers
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