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Kisachek [45]
3 years ago
15

calculate the force between two objects that have masses of 20 kg and 100 kg separated by a distance of 2.6 m

Physics
1 answer:
olga55 [171]3 years ago
7 0

The gravitational force between the objects is 1.97\cdot 10^{-8} N

Explanation:

The magnitude of the gravitational force between two objects is given by the equation:

F=G\frac{m_1 m_2}{r^2}

where

G=6.67\cdot 10^{-11} m^3 kg^{-1}s^{-2} is the gravitational constant

m_1, m_2 are the masses of the two objects

r is the separation between the objects

For the two objects in this problem:

m_1 = 20 kg\\m_2 = 100 kg

And their distance is

r = 2.6 m

So, the gravitational force between them is

F=\frac{(6.67\cdot 10^{-11})(20)(100)}{2.6^2}=1.97\cdot 10^{-8} N

Learn more about gravitational force:

brainly.com/question/1724648

brainly.com/question/12785992

#LearnwithBrainly

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A solid copper cube is attached to spring-like device and is able to oscillate horizontally with negligible friction. Each side
Kazeer [188]

Answer:

6.91 Hz

Explanation:

Volume of the cube

= (1.5 x 10⁻² )³m³

= 3.375 x 10⁻⁶ m³

mass of the cube

= 3.375 x 10⁻⁶  x 8920 ( 8.92 g / cm³ = 8920 kg/m³ )

m = 30.105 x 10⁻³ kg

Spring stretches by 2.65 x 10⁻² m due to a force of  1.5 N.

If k be the force constant

k x = F

K x2.65 x 10⁻²  = 1.5

k = .566 x 10² N / m

Now frequency of oscillation for spring - mass system is given by

n = \frac{1}{2\pi} \sqrt{\frac{k}{m} }

=\frac{1}{2\pi} \sqrt{\frac{56.6}{.03} }

n = 6.91 Hz

4 0
3 years ago
In a city park a nonuniform wooden beam 5.00 m long is suspended horizontally by a light steel cable at each end. The cable at t
DanielleElmas [232]

Answer:

Explanation:

System of forces in balance

ΣFx = 0

ΣFy = 0

∑MA = 0

MA = F*d

Where:

∑MA  : Algebraic sum of moments in the the point (A)

MA : moment in the point A ( N*m)

F  : Force ( N)

d  : Horizontal distance of the force to the point A ( N*m

Forces acting on the beam

T₁ = 620 N : Tension in cable 1 ,at angle of 30° with the vertical on the left

T₂ : Tension in cable 2, at angle of 50.0° with the vertical on the right.

W : Weight of the beam

x-y T₁ and T₂ components

T₁x= 620*sin30° = 310 N

T₁y= 620*cos30° = 536.94 N

T₂x= T₂*sin50°

T₂y= T₂*cos50°

Calculation of the T₂

ΣFx = 0  

T₂x-T₁x = 0

T₂x=T₁x

T₂*sin50° =  310 N

T₂ =  310 N /sin50°

T₂ = 404.67 N

Calculation of the W

ΣFy = 0  

T₂y+T₁y-W = 0

(404.67) *cos50° +  536.94 = W

W= 260.12+ 536.94

W= 797.06 N

Location of the center of gravity of the beam

∑MA = 0 , point (A) (point where the  cable 2  of the right is located on the beam)

T₁y(5)-W(d) = 0

T₁y(5) = W(d)

d = T₁y(5)/W

d =  536.94(5) / 797.06

d = 3.37m

The center of gravity is located at 3.37m measured from the right end of the beam

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3 years ago
The meaning of magnetism
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Magnetism is <span>a physical phenomenon produced by the motion of electric charge, resulting in attractive and repulsive forces between objects.</span>
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3 years ago
8. do the earth and the moon always cast shadows? what do we call the occurrence where the earth passes within the shadow of the
Oduvanchick [21]

Yes, they both cast shadows. A  eclipse occurs when one enters the shadow of the other.

Solar eclipse: Earth in shadow of Moon.

Lunar eclipse: Moon in shadow of Earth.

A solar eclipse is the result of one celestial body being completely or partially obscured by another celestial body along the line of sight of an observer. A solar eclipse occurs when the moon passes between the earth and the sun, obscuring all or part of the sun's disk. A lunar eclipse occurs when the Moon passes through the Earth's shadow, making the Moon's surface completely or partially obscured.

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8 0
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The weightlifter's internal store of energy decreased when he lifted the bar.
Mumz [18]

Answer:

The energy returns to the weightlifter's muscles, where it is dissipated as heat.

Explanation:

The energy returns to the weightlifter's muscles, where it is dissipated as heat. As long as the weightlifter controls the weight's descent, their muscles are acting as an overdamped shock absorber, as if the weight were sitting on a piston containing very thick fluid, slowly compressing it downward (and slightly heating up the fluid in the process). Since muscles are complicated biological systems and not simple pistons, they require metabolic energy to maintain tension throughout the controlled descent, so the weightlifter feels like they're putting energy into the weight, even though the weight's gravitational potential energy is being converted into heat within the lifter's muscles.

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