A differential leveling circuit began on BM Rock (elevation 243.897 m) and closed on BM Manhole (elevation 240.100 m).The plus s
ight and minus sight distances were kept approximately equal. Readings (in meters) listed in the order taken are 0.288 (+S) on BM Rock, 0.987 (-S) and 0.305 (+S) on TP1, 1.405 (-S) and 0.596 (+S) on BM 1, 1.605 (-S) and 0.661 (+S) on BM2, and 1.992 (-S) and 1.056 (+S) on TP2, and 0.704 (-S) on BM Manhole. Prepare, check and adjust the notes.
1 answer:
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Answer:
See attachment for chart
Explanation:
The IPO chart implements he following algorithm
The expressions in bracket are typical examples
<u>Input</u>
Input Number (5, 4.2 or -1.2) --- This will be passed to the Processing module
<u>Processing</u>
Assign variable to the input number (x)
Calculate the square (x = 5 * 5)
Display the result (25) ----> This will be passed to the output module
<u>Output</u>
Display 25
Answer:
The elevation at the high point of the road is 12186.5 in ft.
Explanation:
The automobile weight is 2500 lbf.
The automobile increases its gravitational potential energy in . It means the mobile has increased its elevation.
The initial elevation is of 5183 ft.
The first step is to convert Btu of potential energy to adequate units to work with data previously presented.
British Thermal Unit -
Now we have the gravitational potential energy in lbf*ft. Weight of the mobile is in lbf and the elevation is in ft. We can evaluate the expression for gravitational potential energy as follows:
Where m is the mass of the automobile, g is the gravity, W is the weight of the automobile showed in the problem.
is the final elevation and
is the initial elevation.
Replacing W in the Ep equation
Finally, the next step is to replace the variables of the problem.
The elevation at the high point of the road is 12186.5 in ft.