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Basile [38]
4 years ago
12

Which of the following statements about glycogen metabolism is FALSE?

Engineering
1 answer:
Ratling [72]4 years ago
3 0

Answer:

Glycogen is the primary energy source for muscle and liver cells.

Explanation:

Glycogen is a readily mobilized storage form of glucose. It is a very large, branched polymer of glucose residues that can be broken down to yield glucose molecules when energy is needed. Most of the glucose residues in glycogen are linked by α-1,4-glycosidic bonds. Branches at about every tenth residue are created by α-1,6-glycosidic bonds.

Glycogen is not as reduced as fatty acids are and consequently not as energy rich. Why do animals store any energy as glycogen? Why not convert all excess fuel into fatty acids? Glycogen is an important fuel reserve for several reasons. The controlled breakdown of glycogen and release of glucose increase the amount of glucose that is available between meals. Hence, glycogen serves as a buffer to maintain blood-glucose levels. Glycogen's role in maintaining blood-glucose levels is especially important because glucose is virtually the only fuel used by the brain, except during prolonged starvation. Moreover, the glucose from glycogen is readily mobilized and is therefore a good source of energy for sudden, strenuous activity. Unlike fatty acids, the released glucose can provide energy in the absence of oxygen and can thus supply energy for anaerobic activity.

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A 200-L tank (see Fig. P4.107) initially contains water at 100 kPa and a quality of 1%. Heat is transferred to the water, thereb
Tomtit [17]

Answer:

25.46 MJ

Explanation:

continuity : m3 - m1 = -m<em>e</em>

<em>Energy Equation: m3u3 - m1u1 = -meue + 1Q3</em>

<em />

<em>See the image attached (Well typed out format)</em>

5 0
4 years ago
A horizontal rigid bar ABC is pinned at end A and supported by two cables at points B and C. A vertical load P 5 10 kN acts at e
BARSIC [14]

Answer:

vertical load = 10 kN

Modulus of elasticity = 200GPa

Yield stress on the cable = 400 MPa

Safety factor = 2.0

Explanation:

Data

let L = \sqrt{(1.5)^{2} + (1.5)^{2} }

        = 3.35 m

substituting 1.5 m for h and 3 m for the tern (a + b)

\theta = tan⁻¹(\frac{1.5}{1.5})

  = 45⁰

substituting 1.5 for h and 3 m for (a+ b) yields:

\theta₂ = tan⁻¹ (\frac{1}{3})

   =25.56⁰

checking all the forces, they add up to zero. This means that the system is balanced and there is no resultant force.

6 0
3 years ago
Stream Piracy – Kaaterskill, NY. Check and double-click the Problem 15 folder. The dark blue and orange streams highlight the pr
baherus [9]

Answer:

b. The pirating streams are eroding headwardly to intersect more of the other streams’ drainage basins, causing water to be diverted down their steeper gradients.

Explanation:

From the Kaaterskill NY 15 minute map (1906), this shows two classic examples of stream capture.

The Kaaterskill Creek flow down the east relatively steep slopes into the Hudson River Valley. While, the Gooseberry Creek is a low gradient stream flowing down the west direction which in turn drains the higher parts of the Catskills in this area.

However, there is Headward erosion of Kaaterskill Creek which resulted to the capture of part of the headwaters of Gooseberry Creek.

The evidence for this is the presence of "barbed" (enters at obtuse rather than acute angle) tributary which enters Kaaterskill Creek from South Lake which was once a part of the Gooseberry Creek drainage system.

It should be noted again, that there is drainage divide between the Gooseberry and Kaaterskill drainage systems (just to the left of the word Twilight) which is located in the center of the valley.

As it progresses, this divide will then move westward as Kaaterskill captures more and more of the Gooseberry system.

5 0
3 years ago
What dimensions are used when measuring the area of a building
scoundrel [369]

Answer:According to NEC 220.12,

“the floor area shall be calculated from outside dimensions of the buildings, dwelling unit, or other area involved.

The area should not include open porches, garages or unused or unfinished spaces not adaptable for future use”.

pa brainliest plss..thankss

Explanati

4 0
2 years ago
Read 2 more answers
1) Find the time in seconds to reach full charge in an RL circuit with L = 5 H and R = 100 ohms
pav-90 [236]

The time constant to reach full charge in an RL circuit is 0.05 ms.

Explanation:

To find the time constant,

The time constant for an RL circuit is defined by τ = L/R.

The given data is

L= 5 H

R= 100 ohms

by using the formula,

τ = L/R

  = 5/100

  = 0.05 ms

τ = 0.05 ms

Thus, the time constant to reach full charge in an RL circuit is 0.05 ms.

8 0
3 years ago
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