Answer:
25.46 MJ
Explanation:
continuity : m3 - m1 = -m<em>e</em>
<em>Energy Equation: m3u3 - m1u1 = -meue + 1Q3</em>
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<em>See the image attached (Well typed out format)</em>
Answer:
vertical load = 10 kN
Modulus of elasticity = 200GPa
Yield stress on the cable = 400 MPa
Safety factor = 2.0
Explanation:
Data
let L = 
= 3.35 m
substituting 1.5 m for h and 3 m for the tern (a + b)
= tan⁻¹(
)
= 45⁰
substituting 1.5 for h and 3 m for (a+ b) yields:
₂ = tan⁻¹ (
)
=25.56⁰
checking all the forces, they add up to zero. This means that the system is balanced and there is no resultant force.
Answer:
b. The pirating streams are eroding headwardly to intersect more of the other streams’ drainage basins, causing water to be diverted down their steeper gradients.
Explanation:
From the Kaaterskill NY 15 minute map (1906), this shows two classic examples of stream capture.
The Kaaterskill Creek flow down the east relatively steep slopes into the Hudson River Valley. While, the Gooseberry Creek is a low gradient stream flowing down the west direction which in turn drains the higher parts of the Catskills in this area.
However, there is Headward erosion of Kaaterskill Creek which resulted to the capture of part of the headwaters of Gooseberry Creek.
The evidence for this is the presence of "barbed" (enters at obtuse rather than acute angle) tributary which enters Kaaterskill Creek from South Lake which was once a part of the Gooseberry Creek drainage system.
It should be noted again, that there is drainage divide between the Gooseberry and Kaaterskill drainage systems (just to the left of the word Twilight) which is located in the center of the valley.
As it progresses, this divide will then move westward as Kaaterskill captures more and more of the Gooseberry system.
Answer:According to NEC 220.12,
“the floor area shall be calculated from outside dimensions of the buildings, dwelling unit, or other area involved.
The area should not include open porches, garages or unused or unfinished spaces not adaptable for future use”.
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Explanati
The time constant to reach full charge in an RL circuit is 0.05 ms.
Explanation:
To find the time constant,
The time constant for an RL circuit is defined by τ = L/R.
The given data is
L= 5 H
R= 100 ohms
by using the formula,
τ = L/R
= 5/100
= 0.05 ms
τ = 0.05 ms
Thus, the time constant to reach full charge in an RL circuit is 0.05 ms.