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saveliy_v [14]
3 years ago
5

How did humans create a space suit without ever going. How did we know spaces conditions?

Engineering
2 answers:
brilliants [131]3 years ago
6 0

Answer:

ser gay

Explanation:

no es malo y se fjfjdj gracias

saul85 [17]3 years ago
5 0
Wiley Post experimented with a number of pressure suits for record-breaking flights. Russell Colley created the space suits worn by the Project Mercury astronauts, including fitting Alan Shepard for his ride as America's first man in space
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Carbon and hydrogen!!
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Describe with an example how corroded structures can lead to environment pollution? ​
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An example to describe how it can lead to environment pollution is littering into the oceans , that’s one example how it can help lead to environment pollution , Hope this helps !
8 0
3 years ago
Calculate the length of a metal cylinder while it is subjected to a tensile stress of 10,000 psi. You are given the following da
anastassius [24]

Answer:

length of cylinder can not calculated

Explanation:

given data

tensile stress = 10,000 psi

Original length = 1

Original cross-sectional area = 0.1 in²

Yield strength, σy = 9 ksi

Young’s modulus, E = 1000 ksi

solution

we can see that here that applied stress is greater than yield stress of material  that is express

1000 ksi  >  9 ksi

so here hooks law and strain relation is not working

so length of cylinder can not calculated

as stress applied 10000 psi

5 0
3 years ago
Some aluminum casting alloys can be heat-treated after casting for added strength. Group of answer choices False True
Natasha_Volkova [10]
Some casting alloys can be heat-treated after casting for added strength, True
7 0
3 years ago
A uniform edge load of 500 lb/in. and 350 lb/in. is applied to the polystyrene specimen. If it is originally square and has dime
aliya0001 [1]

The image of the load applied to the polystyrene is missing, so i have attached it.

Answer:

a_new = 2.00302 in

b_new = 2.00552

Explanation:

From the image attached, we can see that the load of 500 lb/in is applied in the x-direction while the load of 350 lb/in acts in the y-direction.

Now, formula for stress is;

Stress(σ) = Force/Area

We are not given force and area but the load and plate thickness.

Thus, stress = load/thickness

We are given;

Load in x - direction = 500 lb/in.

Load in y - direction = 350 lb/in.

Thickness; t = 0.25 in

Thus;

σ_x = 500/0.25

σ_x = 2000 ksi

σ_y = 350/0.25

σ_y = 1400 ksi

From Hooke's law for 2 dimensions, strain is given by the formula;

ε_x = (1/E)(σ_x - vσ_y)

ε_y = (1/E)(σ_y - vσ_x)

We are given v_p = 0.25 and Ep = 597 × 10³ psi

Thus;

ε_x = (1/(597 × 10^(3)))(2000 - (0.25 × 1400)

ε_x = 0.00276

ε_y = (1/(597 × 10^(3)))(1400 - (0.25 × 2000)

ε_y = 0.00151

From elongation formula, we know that;

Startin is: ε = ΔL/L

Thus; ΔL = Lε

We are given a = 2 and b = 2

Thus;

ΔL_x = 2 × 0.00276

ΔL_x = 0.00552

ΔL_y = 2 × 0.00151

ΔL_y = 0.00302

New dimensions are;

a_new = 2 + 0.00302

a_new = 2.00302 in

b_new = 2 + 0.00552

b_new = 2.00552

3 0
3 years ago
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