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Dafna11 [192]
4 years ago
8

A gas tank holds 20000 liters at 850 torr. If the temperature remains constant, what will the volume, in L, of the gas be at sta

ndard pressure, 760 torr?
Chemistry
1 answer:
nekit [7.7K]4 years ago
6 0

Answer: 22368.4 Liters

Explanation:

Initial Volume of gas V1 = 20000 liters

Initial pressure of gas P1 = 850 torr

Final volume V2 = ?

Final (standard) pressure P2 = 760 torr

Apply the formula for Boyle's law:

P1V1 = P2V2

850torr x 20000L = 760torr x V2

V2 = (850torr x 20000L)/ 760torr

V2 = (17000000)/760torr

V2 = 22368.4L

Thus, the volume of the gas at standard pressure is 22368.4 Liters

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What is the value of for this aqueous reaction at 298 K? <br><br>A+B↽⇀C+D ΔG°=12.86 kJ/mol<br><br>K=
agasfer [191]

Answer:

The equilbrium constant is 179.6

Explanation:

To solve this question we can use the equation:

ΔG = -RTlnK

<em>Where ΔG is Gibbs free energy = 12.86kJ/mol</em>

<em>R is gas constant = 8.314x10⁻³kJ/molK</em>

<em>T is absolute temperature = 298K</em>

<em>And K is equilibrium constant.</em>

Replacing:

12.86kJ/mol = -8.314x10⁻³kJ/molK*298K lnK

5.19 = lnK

e^5.19 = K

179.6 = K

<h3>The equilbrium constant is 179.6</h3>

8 0
3 years ago
Use a Punnett square to predict the cross of a homozygous tall parent with a homozygous short parent, if tall is dominant over s
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Answer:

All offspring are tall when a homozygous tall parent with homozygous short parent.

Explanation:

When we crossed  homozygous tall parent with homozygous short parent, we conclude that all offspring are tall, because homozygous short parent are supressed under the homozygous tall parent, due to law of dominance.

Law of dominance states that, recessive alleles are suppressed by dominant alleles but they can appear in F2 generation.

Using a punett square, we can predict the cross between homozygous tall and homozygous short parent.      

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5 0
3 years ago
How many moles of mgs2o3 are in 193 g of the compound?
Mashutka [201]

Answer:

             1.414 Moles

Solution:

Data Given:

                 Mass of MgS₂O₃  =  193 g

                 M.Mass of MgS₂O₃  =  136.43 g.mol⁻¹

                 Moles  =  ?

Formula Used:

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Putting values,

                            Moles  =  193 g ÷ 136.43 g.mol⁻¹

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3 years ago
Calculate the poh of this solution. round to the nearest hundredth. ph = 1.90 poh =
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Answer:

The answer is 5.10

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<h3><u>Given</u>;</h3>
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<h3><u>To </u><u>Find</u>;</h3>
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A scientist finds an unusual object and decides to study it. Which observation indicates that the object is a living thing?
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