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qwelly [4]
3 years ago
9

Describe the path of an electron from a molecule of water to the sugar g3p

Chemistry
1 answer:
aalyn [17]3 years ago
4 0

Answer:

The electron moves by charge attraction

Explanation:

The electrons move by static attraction. Electrons are negatively charged particles that are closely connected with the atoms. The electrons are always delocalized. This means that they belong to no particular atom, but instead, are freely moving around. It is the electrons that help with the transfer of charge in the molecule. In addition, it is the delocalized electrons that carry the charge in the solution. Finally, it is the electrons that make the solution to conduct current.

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ILL GIVE BRIANLY, FOLLOW , 5 STARS AND HEARTS
V125BC [204]

Answer:

it can help heat or cool a room.

Explanation:

I think this is right...

7 0
2 years ago
Checking if my answer is correct: I got LARQY, but I'm pretty sure it's wrong. Can somebody please help?
babunello [35]

Answer:

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Explanation:

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8 0
3 years ago
Doping Se with P would produce a(n) ________ semiconductor with ____________ conductivity compared to pure Se.
deff fn [24]
Doping Se (group VI elements) with P(group V)elements would produce a P-TYPE semiconductor with HIGHER conductivity compared to pure Se

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4 0
2 years ago
A 825 g iron block is heated to 352 degrees C and is placed in an insulated container (of negligible heat capacity) containing 4
Stella [2.4K]

Answer : The final equilibrium temperature of the water and iron is, 537.12 K

Explanation :

In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.

q_1=-q_2

m_1\times c_1\times (T_f-T_1)=-m_2\times c_2\times (T_f-T_2)

where,

c_1 = specific heat of iron =  560 J/(kg.K)

c_1 = specific heat of water = 4186 J/(kg.K)

m_1 = mass of iron = 825 g

m_2 = mass of water = 40 g

T_f = final temperature of water and iron = ?

T_1 = initial temperature of iron = 352^oC=273+352=625K

T_2 = initial temperature of water = 20^oC=273+20=293K

Now put all the given values in the above formula, we get:

(825\times 10^{-3}kg)\times 560J/(kg.K)\times (T_f-625K)=-(40\times 10^{-3}kg)\times 4186J/(kg.K)\times (T_f-293K)

T_f=537.12K

Therefore, the final equilibrium temperature of the water and iron is, 537.12 K

8 0
2 years ago
The force of gravity always pulls ____
damaskus [11]
Down...
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3 years ago
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