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VMariaS [17]
3 years ago
10

A pinball bangs against a bumper giving the ball a speed of 42cm/s if the ball has a mass of 50.0g what is the ball’s kinetic en

ergy in joules
Physics
1 answer:
Ann [662]3 years ago
7 0

Explanation:

<h3><u>Given</u><u>:</u><u>-</u></h3>

mass=50g

velocity=42cm/s

<h3><u>To</u><u> </u><u>find</u><u>:</u><u>-</u></h3>

Kinetic energy

<h3><u>Solution</u><u>:</u><u>-</u></h3>

As we know that

{\boxed{\sf kinetic\:energy={\dfrac {1}{2}}mv^2}}

  • Substitute the values

{:}\longrightarrow\sf k.v={\dfrac {1}{{\cancel{2}}}}\times 50\times {\cancel{42}}^2

{:}\longrightarrow\sf k.v=50\times 21^2

{:}\longrightarrow\sf k.v=50×441

{:}\longrightarrow\sf k.v=22050MJ

  • 1Joule=1000milijoules
  • 22050MJ={\dfrac {22050}{1000}}=22.05J
  • =22J(Approximately)

\therefore{\underline{\boxed{\bf Kinetic\:energy=22Joule}}}

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Answer:

0.16joules

Explanation:

Using the relation for The gravitational potential energy

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h = Vertical Height

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To find the vertical component of angle of launch Where the angle is 22°

h= sin theta

So E = mghsintheta

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Explanation:

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You have a sealed glass jar full of air. If you put it in the freezer, what happens to the gas pressure in the jar?
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A drowsy cat spots a flowerpot that sails first up and then down past an open window. the pot was in view for a total of 0.49 s,
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For this case, let's assume that the pot spends exactly half of its time going up, and half going down, i.e. it is visible upward for 0.245 s and downward for 0.245 s. Let us take the bottom of the window to be zero on a vertical axis pointing upward. All calculations will be made in reference to this coordinate system. <span>

An initial condition has been supplied by the problem: 

s=1.80m when t=0.245s 

<span>This means that it takes the pot 0.245 seconds to travel upward 1.8m. Knowing that the gravitational acceleration acts downward constantly at 9.81m/s^2, and based on this information we can use the formula:

s=(v)(t)+(1/2)(a)(t^2) 

to solve for v, the initial velocity of the pot as it enters the cat's view through the window. Substituting and solving (note that gravitational acceleration is negative since this is opposite our coordinate orientation): 

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v=8.549m/s 

<span>Now we know the initial velocity of the pot right when it enters the view of the window. We know that at the apex of its flight, the pot's velocity will be v=0, and using this piece of information we can use the kinematic equation:

(v final)=(v initial)+(a)(t) 

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0=(v)+(a)(t) 

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<span>Using this information and the kinematic equation we can find the total height of the pot’s flight:

s=(v)(t)+(1/2)(a)(t^2) </span></span></span></span>

s=8.549m/s (0.8714s)-0.5(9.81m/s^2)(0.8714s)^2

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Answer:

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Answer:

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Explanation:

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