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4 years ago

8

Why do we use microwaves to communicate berween earth and satellites

2 answers:

nlexa [21]4 years ago

7 0

It’s frequency is high and microwaves can pass through the atmosphere of the Earth.

valentinak56 [21]4 years ago

3 0

That is the main reason why microwaves are chosen for satellite communication. Its frequency is high and microwaves can pass through the atmosphere of Earth to reach higher orbit satellites. ... Radio waves (other than microwaves )get affected by ionosphere and hence isn't used.

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13. If a track athlete runs an 800 m race at a constant speed of 2 m/s, how long will it

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A. 6.7 min

Explanation:

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Use the drop down menu to complete the sentence. Resistance is measured in units called...

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A banked circular highway curve is designed for traffic moving at 58 km/h. The radius of the curve is 201 m. Traffic is moving a

skelet666 [1.2K]

Answer:0.077

Explanation:

Given

banked designed for traffic moving at $58 km/h\approx 16.11 m/s$

Radius of the curve 201 m

Actual traffic velocity = $37 km/h approx 10.27 m/s$

For banking of road

$tan\theta =\frac{v^2}{rg}$

$tan\theta =\frac{16.11^2}{201\times 9.81}$

$\theta =7.49^{\circ}$

Centripetal acceleration is given by

$a=\frac{v^2}{r}$

Taking component of centripetal acceleration

along and perpendicular to surface

$a_{parallel}=\frac{v^2cos\theta }{r}$

$a_{perpendicular}=\frac{v^2sin\theta }{r}$

From FBD

$mgsin\theta -f_s=ma_{parallel}$

$f_s=mgsin\theta -ma_{parallel}$ ----1

where $f_s$ is frictional force

$N-mgcos\theta =ma_{perpedicular}$

$N=mgcos\theta +ma_{perpedicular}$ ----2

and we know coefficient of friction is given by

$\mu =\frac{f_s}{N}$

$\mu =\frac{mgsin\theta -ma_{parallel}}{mgcos\theta +ma_{perpedicular}}$

$\mu =\frac{gsin\theta -\frac{v^2cos\theta }{r}}{gcos\theta +\frac{v^2sin\theta }{r}}$

$\mu =\frac{1.2804-0.5202}{9.726+0.068}$

$\mu =0.077$

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3 years ago

When a bow is stretched it stores 10j and the arrows mass is 50g as it is projected show that the arrow has a speed of 20m/s

asambeis [7]

Answer:

20 m/s

Explanation:

The stored energy is transformed to kinetic energy and since kinetic energy is given by

$0.5mv^{2}$

where m is the mass of arrow in Kg and v is the velocity of the arrow in m/s. From the principle of energy, all the energy is transformed to KE.

KE= Energy stored in bow

Changing mass from 50 g to Kg we divide by 1000 hence m=50/1000=0.05 Kg

Substituting 0.05 Kg for m and 10 J for KE then we have

0.5\times 0.05\times v^{2}=10 J

Making v the subject of the formula then

$v=\sqrt {\frac {10 J}{0.5\times 0.05 Kg}}=20\ m/s$

Therefore, the velocity is equivalent to 20 m/s

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3 years ago