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denis-greek [22]
3 years ago
14

If a chemical reaction goes to completion, what can we say about the equilibrium constant for that reaction?

Chemistry
1 answer:
aniked [119]3 years ago
7 0

Answer:

A. The equilibrium constant is very large

Explanation:

The equilibrium constant value is the ratio of the concentrations of the products over the reactants. When a chemical reaction goes to completion, that means that all the reactant has turned into products. As the equilibrium constant defines, it is the ratio of the product to the reactant. So at the final stage of the chemical reaction, the equilibrium constant will be very large.

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A goup of cells that work together to perform a specific function.
algol13

Answer:

Cell Differentiation and Tissue.

Explanation:

tissues are organized communities of cells that work together to carry out a specific function.

4 0
3 years ago
What is the molar mass for FeBr3
AleksAgata [21]
Mass of Iron (Fe): 55.845Mass of Bromine (Br): 79.904
You need to multiply the mass of Br by 3 because there are 3 Bromine atoms. 
(79.904)(3)+ 55.845= 239.712+55.845                                = 295.557 g/mol

6 0
3 years ago
How many moles are in 24.75 g of H2O? What is given the conversation and the unknown?
riadik2000 [5.3K]

Answer:

1.373 mol H₂O

General Formulas and Concepts:

<u>Chemistry - Atomic Structure</u>

  • Reading a Periodic Table
  • Using Dimensional Analysis

Explanation:

<u>Step 1: Define</u>

24.75 g H₂O

<u>Step 2: Identify Conversions</u>

Molar Mass of H - 1.01 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of H₂O - 2(1.01) + 16.00 = 18.02 g/mol

<u>Step 3: Convert</u>

<u />24.75 \ g \ H_2O(\frac{1 \ mol \ H_2O}{18.02 \ g \ H_2O} ) = 1.37347 mol H₂O

<u>Step 4: Check</u>

<em>We are given 4 sig figs. Follow sig fig rules and round.</em>

1.37347 mol H₂O ≈ 1.373 mol H₂O

7 0
2 years ago
J.J. Thomson's model of the atom includes all BUT ONE of these features. That is
kakasveta [241]

Answer:

D

Explanation:

usa testprep!!!!!

8 0
3 years ago
What pressure will be exerted by 0.675 moles of a gas at 25*C if it is in a 0.750-L container?
Westkost [7]
PV=nRT

P=nRT/V

P=[(0.650mol)(0.08206)(298K)]/(0.750L)=21.2atm



6 0
3 years ago
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