If a chemical reaction goes to completion, what can we say about the equilibrium constant for that reaction?
1 answer:
You might be interested in
Answer:
- 10.19 g CO₂
- 4.69 g H₂O
Explanation:
The combustion reaction of Octane is:
- C₈H₁₈ → 8CO₂ + 9H₂O
To calculate the mass of CO₂ and H₂O produced, we need to know the mass of octane combusted.
We calculate the mass of Octane from the given volume and density, using the following <em>conversion factors</em>:
- 1 gallon = 3.785 L
- 1 L = 1000 mL
Now we<u> convert 1.24 gallons to mL</u>:
- 1.24 gallon *
4693.4 mL
We <u>calculate the mass of Octane</u>:
- 4693.4 mL * 0.703 g/mL = 3.30 g Octane
Now we use the <em>stoichiometric ratios</em> and <em>molecular weights</em> to <u>calculate the mass of CO₂ and H₂O</u>:
- CO₂ ⇒ 3.30 g Octane ÷ 114g/mol *
* 44 g/mol = 10.19 g CO₂
- H₂O ⇒ 3.30 g Octane ÷ 114g/mol *
* 18 g/mol = 4.69 g H₂O