Answer:
a
Explanation
Bc I took the test, good luck with that guys
Answer:
1) Moles of CO 2 = Given mass / Molecular mass of CO 2 = 4.4 / 44 = 0.1 mole. 2) Molecules of CO2 in 0.1 moles of CO2 = 0.1 x 6.023 x 10 23 = 6.023 x 10 22 molecules 3) 44 gram (molecular wt of CO 2) contains 2 moles atom of oxygen therefore 4.4 gram of CO2 will contain = 2 /44 *4.4 = 0.2 moles atom of Oxygen.
Answer:
M(Fe₂O₃) = 159.70 g/mol
M(CO) = 28.01 g/mol
M(Fe) = 55.85 g/mol
M(CO₂) = 44.01 g/mol
Explanation:
We can calculate the molar mass of a compound by summing the molar masses of the elements that form it.
Fe₂O₃
M(Fe₂O₃) = 2 × M(Fe) + 3 × M(O) = 2 × 55.85 g/mol + 3 × 16.00 g/mol = 159.70 g/mol
CO
M(CO) = 1 × M(C) + 1 × M(O) = 1 × 12.01 g/mol + 1 × 16.00 g/mol = 28.01 g/mol
Fe
M(Fe) = 1 × M(Fe) = 1 × 55.85 g/mol = 55.85 g/mol
CO₂
M(CO₂) = 1 × M(C) + 2 × M(O) = 1 × 12.01 g/mol + 2 × 16.00 g/mol = 44.01 g/mol
A Barometer is used to mesure atmosphereic pressure
1. Acetic acid (Ethanoic acid) is a colorless liquid.
2. Sodium Bicarbonate is an odorless, crystalline powder.
3. Carbon dioxide is a colorless gas.
4. Dihydrogen monoxide is colorless and odorless gas.
5. Sodium acetate is very soluble in water.
6. Calcium chloride has an exothermic reaction when dissolved in water.
7. Calcium carbonate is also an odorless powder.
8. Sodium chloride is soluble in water, and partially soluble (or insoluble) in other liquids.
Hope this helps! (:
