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2 years ago

Here is the whole question

1 answer:

6 0

Saturated oils are oils where every carbon is sp3 hybridized and attached to two other carbons and two hydrogen. An unsaturated oil features a pi bond and a sigma bond between one or more carbons. This sigma bond interacts with Br2 by way of an addition reaction, the double bond is broken and two bromine are added to the carbon chain. The resulting structure is colorless so in a way the oil absorbs the colored Br2 into a colorless molecule. So, the more Saturated an oil is, the more Br2 it can accept and that's why Br2 can be used to detect the presence of satiated oils. While adding Br2, the solution will stay colorless as long as there are double bonds to accept it.

Hope this makes sense, if you've talked about reaction mechanisms this should be pretty straightforward.

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When a given reaction is conducted in a calorimeter, energy is absorbed from the surrounding water and results in a decrease in

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The potential energy of the products is higher than the potential energy of the reactants.

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2 years ago

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Need a bit of help with this. Fill in the coefficients, explain your answer.

sp2606 [1]

Answer:

4Fe + 3O₂ → 2Fe₂O₃

General Formulas and Concepts:

Chemistry - Reactions

Balancing Reactions

Explanation:

Step 1: Define

RxN: Fe + O₂ → Fe₂O₃

Step 2: Balance

We need to balance both Fe and O.

LCM of 2 and 3 is 6:

Fe + 3O₂ → 2Fe₂O₃

We now need the same amount of Fe on both sides:

4Fe + 3O₂ → 2Fe₂O₃

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3 years ago

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Vadim26 [7]

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3 years ago

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The balanced redox reactions for the sequential reduction of vanadium are given below.

Minchanka [31]

Answer : 0.0392 grams of Zn metal would be required to completely reduced the vanadium.

Explanation :

Let us rewrite the given equations again.

$2VO_{2}^{+} (aq)+ 4H^{+}(aq) + Zn (s)\rightarrow 2VO^{2+}(aq)+Zn^{2+}+2H2O(l)$ $2VO^{2+}(aq)+ 4H^{+}(aq) + Zn (s)\rightarrow 2V^{3+} (aq)+Zn^{2+}+2H2O(l)$

$2V^{3+} (aq)+ Zn (s)\rightarrow 2V^{2+}(aq)+Zn^{2+}(aq)$

On adding above equations, we get the following combined equation.

$2VO_{2}^{+} (aq)+ 8H^{+} (aq) + 3Zn (s)\rightarrow 2V^{2+}(aq)+3Zn^{2+}(aq)+4H_{2}O(l)$

We have 12.1 mL of 0.033 M solution of VO₂⁺.

Let us find the moles of VO₂⁺ from this information.

$12.1 mL \times \frac{1L}{1000mL}\times \frac{0.033mol}{L}=0.0003993mol NO_{2}^{+}$

From the combined equation, we can see that the mole ratio of VO₂⁺ to Zn is 2:3.

Let us use this as a conversion factor to find the moles of Zn.

$0.0003993mol NO_{2}^{+}\times \frac{3mol Zn}{2molNO_{2}^{+}}=0.00059895mol Zn$

Let us convert the moles of Zn to grams of Zn using molar mass of Zn.

Molar mass of Zn is 65.38 g/mol.

$0.00059895mol Zn\times \frac{65.38gZn}{1molZn}=0.0392gZn$

We need 0.0392 grams of Zn metal to completely reduce vanadium.

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2 years ago

Write the atomic symbols for isotopes with the following characteristics? 1)an oxygen atom with 10 neutrons 2)a neon atom with t

VARVARA [1.3K]

Isotopes are elements that differ in the number in neutrons while the numner of protons are the same. The answers of the questions are: 1) 18/8 O 2) 22/10 Ne 3) 53/25 Mn 4) 37/24 Cr 5) 106/81 Ti.

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