Answer:
★The second law of refraction
The ratio of sine of angle of incidence to the sine of angle of refraction is a constant for a light of given colour and for a given pair of media. This law is also called Snell's law of refraction. If 'i' is the angle of incidence and 'r' is the angle of refraction then, Sin i/Sin r = constant
This constant value is called the refractive index of the second medium with respect to the first.
Answer:
B. Objects do not have to touch each other to experience a force.
Explanation:
For example ..One of the noncontact forces is magnetic force whereby a magnetic object will be attracted to another magnetic object of oppsite charged particles, through waves called electromagnetic waves. On the other hand, the two magnetic objects of similar charged particles can repel through electromagnetic waves..
It takes the car 14 seconds to stop
Explanation:
A car is traveling at a constant velocity of 19 m/s when the driver puts
on the brakes to accelerate it at -1.4 m/s² until stopped
1. The initial velocity is 19 m/s
2. The acceleration is -1.4 m/s²
3. The final velocity is zero
We need to find how long it takes the car to stop
We can find the time by using the rule
→ v = u + a t
where v is the final velocity, u is the initial velocity, a is the
acceleration and t is the time
→ v = 0 m/s , u = 19 m/s , a = -1.4 m/s²
Substitute these values in the rule
→ 0 = 19 + (-1.4) t
→ 0 = 19 - 1.4 t
Add 1.4 t to both sides
→ 1.4 t = 19
Divide both sides by 1.4
→ t = 13.57 ≅ 14 seconds
It takes the car 14 seconds to stop
Learn more:
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Answer</h2>
The answer is 29495.3 kg
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Explanation</h2>
As we know, the Newton's Second Law of Motion


The F exerted by catapult = 9.35 * 
The Time is = 2.10 s
Velocity of the catapult = 240 km/h = 66.6 m/s (240*1000 m /3600 s)
The mass of jet = ?
First detrmine the acceleration as
{/tex}Acceleration = Velocity/Time {/tex}


Rearrange the formaula as



The mass will be 29495.3 kg
Answer:

Explanation:
It is given that,
Angular speed of the football spiral, 
Radius of a pro football, r = 8.5 cm = 0.085 m
The velocity is given by :


v = 3.68 m/s
The centripetal acceleration is given by :



So, the centripetal acceleration of the laces on the football is
. Hence, this is the required solution.