Yes, with simple machines
Answer:
the field at the center of solenoid 2 is 12 times the field at the center of solenoid 1.
Explanation:
Recall that the field inside a solenoid of length L, N turns, and a circulating current I, is given by the formula:
Then, if we assign the subindex "1" to the quantities that define the magnetic field (
) inside solenoid 1, we have:
![B_1=\mu_0\, \frac{N_1}{L_1} I_1](https://tex.z-dn.net/?f=B_1%3D%5Cmu_0%5C%2C%20%5Cfrac%7BN_1%7D%7BL_1%7D%20I_1)
notice that there is no dependence on the diameter of the solenoid for this formula.
Now, if we write a similar formula for solenoid 2, given that it has :
1) half the length of solenoid 1 . Then ![L_2=L_1/2](https://tex.z-dn.net/?f=L_2%3DL_1%2F2)
2) twice as many turns as solenoid 1. Then ![N_2=2\,N_1](https://tex.z-dn.net/?f=N_2%3D2%5C%2CN_1)
3) three times the current of solenoid 1. Then ![I_2=3\,I_1](https://tex.z-dn.net/?f=I_2%3D3%5C%2CI_1)
we obtain:
![B_2=\mu_0\, \frac{N_2}{L_2} I_2\\B_2=\mu_0\, \frac{2\,N_1}{L_1/2} 3\,I_1\\B_2=\mu_0\, 12\,\frac{N_1}{L_1} I_1\\B_2=12\,B_1](https://tex.z-dn.net/?f=B_2%3D%5Cmu_0%5C%2C%20%5Cfrac%7BN_2%7D%7BL_2%7D%20I_2%5C%5CB_2%3D%5Cmu_0%5C%2C%20%5Cfrac%7B2%5C%2CN_1%7D%7BL_1%2F2%7D%203%5C%2CI_1%5C%5CB_2%3D%5Cmu_0%5C%2C%2012%5C%2C%5Cfrac%7BN_1%7D%7BL_1%7D%20I_1%5C%5CB_2%3D12%5C%2CB_1)
Answer:
The correct answer is Dean has a period greater than San
Explanation:
Kepler's third law is an application of Newton's second law where the force is the universal force of attraction for circular orbits, where it is obtained.
T² = (4π² / G M) r³
When applying this equation to our case, the planet with a greater orbit must have a greater period.
Consequently Dean must have a period greater than San which has the smallest orbit
The correct answer is Dean has a period greater than San
Technically speaking, there are many "levels" of a plant for which this may hold true. I think the one you are referring to is the chloroplast. It takes in the light energy from the sun, water and carbon dioxide, and performs photosynthesis on them to produce sugar and oxygen. A leaf would also fit the description as this is a very general question.
Answer:
Solid objects will deform when adequate loads are applied to them; if the material is elastic, the object will return to its initial shape and size after removal. This is in contrast to plasticity, in which the object fails to do so and instead remains in its deformed state.
Explanation: