Well one situation i can think of is a tire rolling on a car
(ill try to find more)
Answer:
The maximum electric field 
Explanation:
From the question we are told that
The diameter is 
The magnetic field of the cylinder is
The frequency is 
The radial distance is 
This magnetic field can be represented mathematically as

The initial magnetic field is the average between the variation of the magnetic field which is represented as


Then
is the amplitude of the resultant field is mathematically evaluated as


The electric field induced can be represented mathematically as
![E = \frac{1}{2} [\frac{dB }{dt} ]d_r](https://tex.z-dn.net/?f=E%20%3D%20%5Cfrac%7B1%7D%7B2%7D%20%20%5B%5Cfrac%7BdB%20%7D%7Bdt%7D%20%20%5Dd_r)


At maximum electric field 




To solve this problem it is necessary to apply the concepts related to the conservation of angular momentum. This can be expressed mathematically as a function of inertia and angular velocity, that is:

Where,
I = Moment of Inertia
= Angular Velocity
For the given object the moment of inertia is equivalent to

Considering that the moment of inertia varies according to distance, and that there are two of these without altering the mass we will finally have to




Our values are given as,

Replacing we have,


Therefore the angular speed after the catch slips is 0.2rad/s
Answer:
Work Done = W
force = F
Distance = d
W = Fd
or W = F*d
W (in joules) = 3.5*4 = 14 Nm (or J)
1Nm = 1J
so newton meters and joules are the same
Power = Work (in joules) /time (in seconds)
i don’t know the time so i can’t solve it
Answer:
Acceleration is 1.2 m/s^2.
Explanation:
initial velocity, u = 0
distance, d = 60 m
time, t = 10 s
Let the acceleration is a.
use second equation of motion

Now according to the Newton's second law
Force = mass x acceleration
Let the mass is m.
F = m x 1.2 = 1.2 m Newton