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MariettaO [177]
4 years ago
11

There are 45 new houses being built in a neighborhood. Last month, 1/3 of them were sold. This month, 1/5 of the remaining house

s were sold. How many houses are left be sold?
Mathematics
1 answer:
Makovka662 [10]4 years ago
8 0
45 new houses.....last month 1/3 were sold....
1/3(45) = 45/3 = 15 houses sold last month

this month, 1/5 of the remaining houses were sold...
remaining houses left are (45 - 15) = 30
1/5(30) = 30/5 = 6 houses sold this month

houses left : 45 - 15 - 6 = 45 - 21 = 24 houses remain <==
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The sample standard deviation is 393.99

Step-by-step explanation:

The standard deviation of a sample can be calculated using the following formula:

s=\sqrt[ ]{\frac{1}{N-1} \sum_{i=1}^{N}(x_{i}-{\displaystyle \textstyle {\bar {x}}}) ^{2} }

Where:

s= Sample standart deviation

N= Number of observations in the sample

{\displaystyle \textstyle {\bar {x}}}= Mean value of the sample

and \sum_{i=1}^{N}(x_{i}-{\displaystyle \textstyle {\bar {x}}}) ^{2} } simbolizes the addition of the square of the difference between each observation and the mean value of the sample.

Let's start calculating the mean value:

\bar {x}=\frac{1}{N}  \sum_{i=1}^{N}x_{i}

\bar {x}=\frac{1}{15}*(180+1600+90+140+50+260+400+90+380+110+10+60+20+340+80)

\bar {x}=\frac{1}{15}*(3810)

\bar {x}=254

Now, let's calculate the summation:

\sum_{i=1}^{N}(x_{i}-\bar {x}) ^{2} }=(180-254)^2+(1600-254)^2+(90-254)^2+...+(80-254)^2

\sum_{i=1}^{N}(x_{i}-\bar {x}) ^{2} }=2173160

So, now we can calculate the standart deviation:

s=\sqrt[ ]{\frac{1}{N-1} \sum_{i=1}^{N}(x_{i}-{\displaystyle \textstyle {\bar {x}}}) ^{2} }

s=\sqrt[ ]{\frac{1}{15-1}*(2173160)}

s=\sqrt[ ]{\frac{2173160}{14}}

s=393.99

The sample standard deviation is 393.99

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Answer:

Step-by-step explanation:

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