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4 years ago

Is it really possible for humans not to alter the natural world around them?

Chemistry

1 answer:

tankabanditka [31]4 years ago

6 0

Answer: I'm sure it's possible but we too lazy

Explanation:

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A bike lost 20% of its value after the first year, its value after the first year is $1039. Calculate the original price of the

musickatia [10]

Answer:

$1246.90

Explanation:

Since the bike lost $20%$ % of it's value and it now currently at $ $$1039$ , we have to do 20% * $1039 to find the amount of money lost. 20%*1039=207.8. We have to add it up to find the original value so 1039+207.8=$1246.8

6 0

3 years ago

How many atoms are in 6.4 moles of vanadium

den301095 [7]

6.4 * 6.02 * 10^23 = 3.8528*10^24 atoms
Don't let the fact that it's vanadium throw you off, avagadros constant stays the same for all elements

3 0

3 years ago

If an isotope of uranium, uranium-235, has 92 protons, how many protons does the isotope uranium-28 have?

padilas [110]

92. All isotopes of uranium have the same number of protons

4 0

3 years ago

Copper(ii) chloride reacts with sodium nitrate to produce copper(ii) nitrate and sodium chloride.

zlopas [31]

Answer:

CuCl2 + 2NaNO3 - > Cu(NO3)2 + 2NaCl

5 0

3 years ago

A breeder nuclear reactor is a reactor in which nonfissile U-238 is converted into fissile Pu-239. The process involves bombardm

VARVARA [1.3K]

Answer: The nuclear equations for the given process is written below.

Explanation:

The chemical equation for the bombardment of neutron to U-238 isotope follows:

$_{92}^{238}\textrm{U}+n\rightarrow _{92}^{239}\textrm{U}$

Beta decay is defined as the process in which neutrons get converted into an electron and a proton. The released electron is known as the beta particle.

$_Z^A\textrm{X}\rightarrow _{Z+1}^A\textrm{Y}+_{-1}^0\beta$

The chemical equation for the first beta decay process of $_{92}^{239}\textrm{U}$ follows:

$_{92}^{239}\textrm{U}\rightarrow _{93}^{239}\textrm{Np}+_{-1}^0\beta$

The chemical equation for the second beta decay process of $_{93}^{239}\textrm{Np}$ follows:

$_{93}^{239}\textrm{Np}\rightarrow _{94}^{239}\textrm{Pu}+_{-1}^0\beta$

Hence, the nuclear equations for the given process is written above.

6 0

3 years ago