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Yuki888 [10]
3 years ago
6

A sample of a compound contains 160 g of oxygen and 20.2 g of hydrogen. Give the compound's empirical formula.

Chemistry
2 answers:
Stella [2.4K]3 years ago
4 0

Answer : The empirical formula of a compound is, H_2O_1

Solution : Given,

Mass of O = 160 g

Mass of H = 20.2 g

Molar mass of O = 16 g/mole

Molar mass of H = 1 g/mole

Step 1 : convert the given masses into moles.

Moles of O = \frac{\text{ given mass of O}}{\text{ molar mass of O}}= \frac{160g}{16g/mole}=10moles

Moles of H = \frac{\text{ given mass of H}}{\text{ molar mass of H}}= \frac{20.2g}{1g/mole}=20.2moles

Step 2 : For the mole ratio, divide each value of the moles by the smallest number of moles calculated.

For O = \frac{10}{10}=1

For H = \frac{20.2}{10}=2.02\approx 2

The ratio of O : H = 1 : 2

The mole ratio of the element is represented by subscripts in empirical formula.

The Empirical formula = H_2O_1

Therefore, the empirical formula of a compound is, H_2O_1

Maslowich3 years ago
3 0
Amount of oxygen in the compound = 160 g
Amount of oxygen in the compound = 20.2 gm
Mole of oxygen in the compound = 160/16
                                                     = 10 moles
Mole of hydrogen in the compound = 20.2/1.01
                                                         = 20 moles
Then
The ratio of oxygen to ration of hydrogen = 1:2
So
The empirical formula of the compound is H2O. I hope the answer has come to your help.
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Answer:

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Explanation:

If we have the value 4520kj is because the question is related to Energy and heat capacity. In this case, the law and equation that we use is the following:

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5 0
3 years ago
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Julli [10]
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Enthalpy change (ΔH) is simply defined as the difference between the heat of product (Hp) and the heat of reactant (Hr). Mathematically, it is expressed as:

Enthalpy change (ΔH) = Heat of product (Hp) – Heat of reactant (Hr)

ΔH = Hp – Hr

Note: If the enthalpy change (ΔH) is positive, it means that the product has a higher heat content than the reactant.

If the enthalpy change (ΔH) is negative, it means that the reactant has a higher heat content than the product.

Now, considering the question given, the enthalpy change (ΔH) is 89.4 KJ/mol and it is a positive number indicating that the heat content of the product is higher than the heat content of the reactant.

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7 0
3 years ago
Read 2 more answers
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Reversing the reaction, changes the sign of \Delta H

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Thus the enthalpy change for the given reaction is -705.55kJ

7 0
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