Answer:
Therefore the concentration of salt in the incoming brine is 1.73 g/L.
Step-by-step explanation:
Here the amount of incoming and outgoing of water are equal. Then the amount of water in the tank remain same = 10 liters.
Let the concentration of salt be a gram/L
Let the amount salt in the tank at any time t be Q(t).

Incoming rate = (a g/L)×(1 L/min)
=a g/min
The concentration of salt in the tank at any time t is =
g/L
Outgoing rate =



Integrating both sides

[ where c arbitrary constant]
Initial condition when t= 20 , Q(t)= 15 gram


Therefore ,
.......(1)
In the starting time t=0 and Q(t)=0
Putting t=0 and Q(t)=0 in equation (1) we get









Therefore the concentration of salt in the incoming brine is 1.73 g/L
The probability that a biscuit picked at random contains chocolate
chips. = 1/5 , The Venn Diagram is attached with the answer.
<h3>What is Probability ?</h3>
Probability is defined as the study of likeliness of an event to happen.
It is given that
There are 30 biscuits in a tin
8 of the biscuits are iced, of which 6 contain chocolate chips
4 biscuits are neither iced nor contain chocolate chips.
the probability that a biscuit picked at random contains chocolate
chips.
There are total 6 biscuits which have chocolate chips
The probability that a biscuit picked at random contains chocolate
chips. = 6/8 *8/30 = 6/30 = 1/5
The probability that a biscuit picked at random contains chocolate
chips. = 1/5
The Venn Diagram is attached with the answer.
To know more about Probability
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Answer:
<em>K = 4.8</em>
Step-by-step explanation:
<u>Equation Solving</u>
We are given the equation:
F = 95K - 455.67
We are required to find the value of K when F=0:
95K - 455.67 = 0
Adding 455.67:
95K = 455.67
Dividing by 95;
K = 4.8
Answer:
Answer:
y=
d−4
/c+9
Step-by-step explanation:
cy+4=d−9y
Step 1: Add 9y to both sides.
cy+4+9y=d−9y+9y
cy+9y+4=d
Step 2: Add -4 to both sides.
cy+9y+4+−4=d+−4
cy+9y=d−4
Step 3: Factor out variable y.
y(c+9)=d−4
Step 4: Divide both sides by c+9.
y(c+9) c+9
=
d−4
/c+9
y=
d−4
/c+9