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yulyashka [42]
3 years ago
11

How has the coronavirus disrupted the global economy? Provide specific

Chemistry
1 answer:
mixer [17]3 years ago
7 0

Answer:

Restaurants have been closing, less customers are buying, people are forced to close businesses, and fears of getting infected are preventing people of going out.

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Negative radical in the periodic table​
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A radical is a group of atoms of elements carrying a charge, e.g., chlorate [ClO3–]. Radicals or ions are formed by losing or gaining electrons. When an electron is gained the group of atoms acquire a negative charge and is called a negative radical or negative ion.

5 0
3 years ago
Quick help I really need help
Sauron [17]

Answer:

CO2 H2o

Explanation:

8 0
3 years ago
The main goal of developing technology is to___?
sammy [17]

I believe the correct answer is C, but I'm 100% on this.  Hope this helped though!

-TTL

8 0
3 years ago
Read 2 more answers
Calculate the volume of a gas at a pressure of 150 kpa if its volume at 180 kpa is 1500 L
Anastaziya [24]

Answer: 1800 L

Explanation:

Given that,

Original pressure of gas (P1) = 180 kPa

Original volume of gas (V1) = 1500 L

New pressure of gas (P2) = 150 kPa

New volume of gas (V2) = ?

Since pressure and volume are given while temperature is held constant, apply the formula for Boyle's law

P1V1 = P1V2

180 kPa x 1500 L = 150 kPa x V2

270000 kPa•L = 150 kPa•V2

Divide both sides by 150 kPa

270000 kPa•L/150 kPa = 150 kPa•V2/150 kPa

1800L = V2

Thus, the new volume of the gas is 1800 liters.

8 0
3 years ago
What mass of water could be warmed from 21.4 degrees celsius to 43.4 degrees celsius by the pellet dropped inside it? Heat capac
Artist 52 [7]

42.34 g of water could be warmed from 21.4°C to 43.4°C  by the pellet dropped inside it

Heat loss by the pellet is equal to the Heat gained by the water.

q_{w} = -q_{p} ….(1)

where, q_{w} is the heat gained by water

q_{p} is the heat loss by pellet

q_{w} = mCΔT

where m = mass of water

C = specific heat capacity of water = 4.184 J/g-°C

ΔT = Increase in temperature

ΔT for water = 43.4 - 21.4 = 22°C

q_{w} = m × 4.184 × 22 …. (2)

Now

q_{p} = H_{c} ×ΔT

where H_{c} = Heat capacity of pellet = 56J/°C

Δ T for pellet = 43.4 - 113 =- 69.6°C

q_{p} = 56 × -69.6 = -3897.6 J

From equation (1) and (2)

-m× 4.184 × 22 =-3897.6

m= 42.34 g

Hence, 42.34 g of water could be warmed from 21.4 degrees Celsius to 43.4 degrees Celsius by the pellet dropped inside it.

Learn more about specific heat here brainly.com/question/16559442

#SPJ1

6 0
2 years ago
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