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lora16 [44]
3 years ago
14

If the ΔH for

Chemistry
1 answer:
Free_Kalibri [48]3 years ago
8 0

Answer:

ΔH2=772 kJ

Explanation:

Hello,

In this case, since the change in a reaction's enthalpy is given by the subtraction between the product's enthalpies and the reactant's enthalpies, we notice that the second reaction is the same initial reaction but arranged on the contrary way. In means that if the original reaction has:

ΔH1=−772 kJ

It means that the reaction:

2NaCl → 2Na + Cl2

Has an enthalpy of reaction of:

ΔH2=-(−772 kJ)

ΔH2=772 kJ

As the reactants and products were all inverted, so the enthalpy change has the same number but different sign.

Best regards.

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6 0
3 years ago
What floats on top of molten magma under the earth’s surface?.
elena-s [515]

Explanation:

Earthquakes. are caused by the earth's crust, more specifically, tectonic plates that float on top of molten magma. These plates bump into each other. it's the answer Earthquakes.

5 0
2 years ago
sample of atmospheric gas collected at an industrial site is stored in a 250 mL amber glass bottle that has a pressure of 1.02 a
Nady [450]

Answer:- New pressure is 0.942 atm.

Solution:- The volume of the glass bottle would remain constant here and the pressure will change with the temperature.

Pressure is directly proportional to the kelvin temperature. The equation used here is:

P_1T_2=P_2T_1

Where, T_1 and T_2 are initial and final temperatures, P_1 and P_2 are initial and final pressures.

T_1 = 20.3 + 273.15 = 293.45 K

T_2 = -2.0 + 273.15 = 271.15 K

P_1 = 1.02 atm

T_2  = ?

Let's plug in the values in the equation and solve it for final pressure.

1.02atm(271.15K)=P_2(293.45K)

P_2=\frac{1.02atm*271.15K}{293.45K}

P_2 = 0.942 atm

So, the new pressure of the jar is 0.942 atm.


5 0
3 years ago
Which of the following statements describes a physical property?
castortr0y [4]


The substance has a higher density than water


8 0
3 years ago
Read 2 more answers
Calculate the ph of a 0.021 m nacn solution. [ka(hcn) = 4.9  10–10]
ohaa [14]

<span>Answer is: pH of solution of sodium cyanide is 11.3.
Chemical reaction 1: NaCN(aq) → CN</span>⁻(aq) + Na⁺<span>(aq).
Chemical reaction 2: CN</span>⁻ + H₂O(l) ⇄ HCN(aq) + OH⁻<span>(aq).
c(NaCN) = c(CN</span>⁻<span>) = 0.021 M.
Ka(HCN) =  4.9·10</span>⁻¹⁰<span>.
Kb(CN</span>⁻) = 10⁻¹⁴ ÷ 4.9·10⁻¹⁰ = 2.04·10⁻⁵<span>.
Kb = [HCN] · [OH</span>⁻] / [CN⁻<span>].
[HCN] · [OH</span>⁻<span>] = x.
[CN</span>⁻<span>] = 0.021 M - x..
2.04·10</span>⁻⁵<span> = x² / (0.021 M - x).
Solve quadratic equation: x = [OH</span>⁻<span>] = 0.00198 M.
pOH = -log(0.00198 M) = 2.70.
pH = 14 - 2.70 = 11.3.</span>

4 0
3 years ago
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