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lora16 [44]
3 years ago
14

If the ΔH for

Chemistry
1 answer:
Free_Kalibri [48]3 years ago
8 0

Answer:

ΔH2=772 kJ

Explanation:

Hello,

In this case, since the change in a reaction's enthalpy is given by the subtraction between the product's enthalpies and the reactant's enthalpies, we notice that the second reaction is the same initial reaction but arranged on the contrary way. In means that if the original reaction has:

ΔH1=−772 kJ

It means that the reaction:

2NaCl → 2Na + Cl2

Has an enthalpy of reaction of:

ΔH2=-(−772 kJ)

ΔH2=772 kJ

As the reactants and products were all inverted, so the enthalpy change has the same number but different sign.

Best regards.

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What coefficients are needed to balance the equation for the complete combustion of methane? enter the coefficients in the order
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The coefficients in the order CH₄, O₂, CO₂, and H₂O, are 1,2,1,2

The equation becomes:

CH₄ (g) + 2O₂ (g) -> CO₂ (g) + 2H₂0 (g)

<h3><em>Further explanation</em></h3>

Complete combustion of hydrocarbon with oxygen will be obtained by CO₂ and H₂O compounds.

If O is insufficient there will be incomplete combustion produced by CO and H and O

Hydrocarbon combustion reactions (specifically alkanes)

\large {\boxed {\bold {C_nH _ (_2_n _ + _ 2_) + \frac {3n + 1} {2} O_2 ----> nCO_2 + (n + 1) H_2O}}}

Equalization of chemical reaction equations can be done using variables.

Steps in equalizing the reaction equation:

  • 1. gives a coefficient on substances involved in the equation of reaction such as a, b, or c etc.
  • 2. make an equation based on the similarity of the number of atoms where the number of atoms = coefficient × index between reactant and product
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For gas combustion reaction which is a reaction of hydrocarbons with oxygen produces CO₂ and H₂O (water vapor). can use steps:

Balancing C atoms, H and last atoms O atoms

Methana combustion reaction

CH₄ (g) + O₂ (g) -> CO₂ (g) + H₂0 (g)

We give the most complex compounds, namely Methane, we give the number 1

So the reaction becomes

CH₄ (g) + aO₂ (g) -> bCO₂ (g) + cH₂0 (g)

C atom on the left 1, right b, so b = 1

H atom on the left 4, right 2c, so 2c = 4 ---> c = 2

Atom O on the left 2a, right 2b + c, so 2a = 2b + c

2a = 2.1 + 2

2a = 4

a = 2

The equation becomes:

CH₄ (g) + 2O₂ (g) -> CO₂ (g) + 2H₂0 (g)

<h3><em>Learn more</em></h3>

the combustion of octane in gasoline

brainly.com/question/8175791

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hydrogen and excess oxygen

brainly.com/question/1405182

Keywords: methane, combustion, hydrocarbons, equalization of reaction equations

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