Question

Need help asap! A 200 L balloon is blown up inside at 100 K. It is then taken outside in the hot sun and heated to 400K. What is the new volume?
400L
200L
50L
800L

Answer 1

The new volume is 800 L.

From Charles’ Law, we know that

V₁/T₁ = V₂/T₂

Then

V₂ = V₁ × T₂/T₁

V₁ = 200 L; T₁ = 100 K

V₂ = ?;        T₂ = 400 K

∴ V₂ = 200 L × (400 K/100 K) = 800 L

Answer 2

Answer

The volume will be 50 L

Explanation

From Kelvin Law of Temperature, we know that

$V_{1} T_{1} =V_{2} T_{2}$

We know that

$V_{1}$ = 200 L

$T_1$ = 100 K

$T_2$= 400 K

So,

$V_{2} = V_{1} T_{1}/T_{2}$

$V_{2} = 200*100/400$

$V_{2} = 50 L$

The answer of the givern question is 50L