Answer:
PDSA, where you work as a group
Explanation:
Answer:
R = 31.9 x 10^(6) At/Wb
So option A is correct
Explanation:
Reluctance is obtained by dividing the length of the magnetic path L by the permeability times the cross-sectional area A
Thus; R = L/μA,
Now from the question,
L = 4m
r_1 = 1.75cm = 0.0175m
r_2 = 2.2cm = 0.022m
So Area will be A_2 - A_1
Thus = π(r_2)² - π(r_1)²
A = π(0.0225)² - π(0.0175)²
A = π[0.0002]
A = 6.28 x 10^(-4) m²
We are given that;
L = 4m
μ_steel = 2 x 10^(-4) Wb/At - m
Thus, reluctance is calculated as;
R = 4/(2 x 10^(-4) x 6.28x 10^(-4))
R = 0.319 x 10^(8) At/Wb
R = 31.9 x 10^(6) At/Wb
Answer:
4.26
Explanation:
The wavelength λ is given by:
Phase constant (β) = 2π/λ
βl = 2π/λ × l
l = 2 cm = 0.02 m
βl = 2π/0.0625 × 0.02=2.01 rad = 115.3°
1 rad = 180/π degrees
Answer:
(a)
(b)Q= -35.69 KW
Explanation:
Given:
We know that foe air
Mass flow rate for air =2.3 kg/s
(a)
By mass balancing
(b)
Now from first law for open(nozzle) system
Δh=
Q=-15.52 KJ/s
⇒ KW
Q= -35.69 KW
If heat will loss from the system then we will take negative and if heat will incoming to the system we will take as positive.