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boyakko [2]
2 years ago
15

Which of the following relationship types most closely resembles the relationship between the national importance of residential

construction and the national economy?
O indifferent, where each partner has little to do with one another
O parasitic, where one partner exploits the other
O chaotic, where the relations between the partners are unpredictable
O mutually supportive, where each partner helps the other
Engineering
1 answer:
BigorU [14]2 years ago
7 0
I think it’s the last one hope that helps
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Why do we study National studies
Gre4nikov [31]

Answer:

It’s so we can then understand other cultures and other ways that people do things or we can also be prepared for what a country that we have not been to yet is going to relatively be like. This can also help with vacation planning.

Explanation:

it can also help us understand different people from different cultures.

3 0
2 years ago
An aircraft is flying at 300 mph true airspeed has a 50 mph tailwind. What is its ground speed?
Free_Kalibri [48]

Answer:

304.13 mph

Explanation:

Data provided in the question :

The Speed of the flying aircraft = 300 mph

Tailwind of the true airspeed = 50 mph

Now,

The ground speed will be calculated as:

ground speed = \sqrt{300^2+50^2}

or

The ground speed = \sqrt{92500}

or

The ground speed = 304.13 mph

Hence, the ground speed is 304.13 mph

8 0
3 years ago
A pipe of 0.3 m outer diameter at a temperature of 160°C is insulated with a material having a thermal conductivity of k = 0.055
Alekssandra [29.7K]

Answer:

Q=0.95 W/m

Explanation:

Given that

Outer diameter = 0.3 m

Thermal conductivity of material

K= 0.055(1+2.8\times 10^{-3}T)\frac{W}{mK}

So the mean conductivity

K_m=0.055\left ( 1+2.8\times 10^{-3}T_m \right )

T_m=\dfrac{160+273+40+273}{2}

T_m=373 K

K_m=0.055\left ( 1+2.8\times 10^{-3}\times 373 \right )

K_m=0.112 \frac{W}{mK}

So heat conduction through cylinder

Q=kA\dfrac{\Delta T}{L}

Q=0.112\times \pi \times 0.15^2\times 120

Q=0.95 W/m

4 0
3 years ago
Air is compressed in a reversible, isothermal, steady- flow process from 15 psia, 100°F to 100 psia. Calculate the work of compr
mixas84 [53]

Answer:

|W|=169.28 KJ/kg

ΔS = -0.544 KJ/Kg.K

Explanation:

Given that

T= 100°F

We know that

1 °F = 255.92 K

100°F = 310 .92 K

P _1= 15 psia

P _1= 100 psia

We know that work for isothermal process  

W=mRT\ln \dfrac{P_1}{P_2}

Lets take mass is 1 kg.

So work per unit mass

W=RT\ln \dfrac{P_1}{P_2}

We know that for air R=0.287KJ/kg.K

W=RT\ln \dfrac{P_1}{P_2}

W=0.287\times 310.92\ln \dfrac{15}{100}

W= - 169.28 KJ/kg

Negative sign indicates compression

|W|=169.28 KJ/kg

We know that change in entropy at constant volume

\Delta S=-R\ln \dfrac{P_2}{P_1}

\Delta S=-0.287\ln \dfrac{100}{15}

ΔS = -0.544 KJ/Kg.K

3 0
3 years ago
To reduce the negative impacts of stress on your mental
soldi70 [24.7K]

Answer:

A&C

Explanation:

breathing deeply is relaxing

talking with a friend can helping

4 0
2 years ago
Read 2 more answers
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