7. The "3 second rule" is the time you should pause at an intersection marked with a stop sign.

Which distributions would you recommend be tested using Benford’s law? Select all choices that apply. (You may select more than

Leni [432]

Answer:

Please see the attached picture for the complete answer.

Explanation:

6 0

4 years ago

With thermodynamics, one cannot determine ________.

zloy xaker [14]

Answer:

Option B is correct.

Explanation:

With thermodynamics, one cannot determine the speed of the reaction.

Speed of the reaction is defined as the rate at which one component is changes to another component. With factor cannot be calculated from the thermodynamics branch of engineering.

With thermodynamics we can determine the value of the equilibrium constant,

the extent of a reaction, the temperature at which a reaction will be spontaneous & the direction of a spontaneous reaction. But we cannot determine the speed of a reaction.

Therefore option B is correct.

4 0

3 years ago

One horsepower is the ability to lift 550 pounds a height of one foot in one second or one horsepower is equal to 550ft-lb/s. Ho

madam [21]

Answer:

32 horsepower will be equal to 17600 ft-lb/sec

Explanation:

We have given 1 horsepower = 550 ft-lb/sec

We have to convert 32 horsepower into ft-lb/sec

As we know that 1 horsepower is equal to 550 ft-lb/sec

So for converting horsepower to ft-lb/sec we have multiply with 550

We have given 32 horse power

So $32\ horsepower =32\times 550=17600ft-lb/sec$

So 32 horsepower will be equal to 17600 ft-lb/sec

5 0

4 years ago

A 1/20 scale model of a wing is used to determine forces on the actual airplane. the 1/20 scale refers to the:_____

Kryger [21]

Answer:

A Lengths

Explanation:

you make a model to show an object too large to test and too expensive to test

5 0

3 years ago

Read 2 more answers

The transfer function of a linear system is defined as the ratio of the Laplace transform of the output function y(t) over the r

faltersainse [42]

Answer:

H(s) = Y(s)/G(s) = 1/(s² + 8s + 6)

Explanation:

Since we are required to determine the transfer function G(s) and Y(s) = G(s)H(s). So, H(s) = Y(s)/G(s).

Since our system is given as y′′(t) + 8y′(t) +6y(t) = g(t), t>0 with all initial condition zero, that is, y(0) = 0, y"(0) = 0 and g(0) = 0.

Taking the Laplace transform of both the left hand side and right hand side of the equation, we have

y′′(t) + 8y′(t) +6y(t) = g(t),

L{y′′(t) + 8y′(t) +6y(t)} = L{g(t)}

L{y′′(t)} + L{8y′(t)} + L{6y(t)} = L{g(t)}

L{y′′(t)} + 8L{y′(t)} + 6L{y(t)} = L{g(t)}

[s²Y(s) - sy(0) - y'(0)] + 8[sY(s) - y(0)] + 6Y(s) = G(s)

[s²Y(s) - s(0) - 0] + 8[sY(s) - 0] + 6Y(s) = G(s)

s²Y(s) + 8sY(s) + 6Y(s) = G(s)

(s² + 8s + 6)Y(s) = G(s)

Y(s)/G(s) = 1/(s² + 8s + 6)

So, H(s) = Y(s)/G(s) = 1/(s² + 8s + 6)

6 0

3 years ago