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Veseljchak [2.6K]
3 years ago
6

7. The "3 second rule" is the time you should pause at an intersection marked with a stop sign.

Engineering
1 answer:
forsale [732]3 years ago
8 0
A. True because that’s correct
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Determine the minimum number of 120-volt, 20-ampere circuit breakers for a continuous load consisting of 63 feet of track lighti
maks197457 [2]

If  we have 20-ampere circuit breakers. The  number of circuits to the larger whole number is: 13.

<h3>Number of circuits</h3>

Receptacles on a single strap= 180 VA each.

Hence,

VA of the circuit=(Volts x Amperes)/One receptacle

Let plug in the formula

VA of the circuit=(120 volts x 20 amperes)/180 VA

VA of the circuit= 2,400 VA (circuit)/180 VA

VA of the circuit = 13 circuits

Therefore the  number of circuits to the larger whole number is: 13.

Learn more about number of circuits here:brainly.com/question/2969220

brainly.com/question/19790289

#SPJ12

4 0
2 years ago
Write a SELECT statement that returns the same result set as this SELECT statement, but don’t use a join. Instead, use a subquer
Bess [88]

Answer:

See explanation

Explanation:

The complete question is

Write a SELECT statement that returns the same result set as this SELECT statement, but don't use a

join. Instead, use a subquery in a WHERE clause that uses the IN keyword.

SELECT DISTINCT category_name

FROM categories c JOIN products p

ON c.category_id = p.category_id

ORDER BY category_name

The join clause  gives us all the registers of both tables, for which the category_id of categories coincides to  the category_id in the table products. That is, we can first select the distinct category_id's from products and the see the categories from categories table, whose id is in that list. That means writing the following query:

Select distinct category_name

from categories c

where c.category_id in (

select distinct p.category_id

from products p)

order by category_name

4 0
4 years ago
What minimum radius of curvature may be designed for safe operation of vehicles at 70 mi/hr if the maximum rate of superelevatio
aleksandr82 [10.1K]
Tell me why i got this question got it right and now won’t remember but i’ll get back at you when i remember
5 0
3 years ago
The alignment readings for the front of a vehicle are shown above. Camber and toe are within specification, caster is not. Techn
dlinn [17]

Answer:

B. B only

Given Information:

1. Camber and toe are within specification

2. Caster is not within specification

Technician A says that with the current settings, the left front tire tread may wear on the inside edge.

Technician B says that with the current settings, the vehicle may pull to the left

Explanation:

Lets discuss the effects of Camber, toe and caster misalignment

Effects of Camber and Toe misalignment:

Camber is the inward or outward tilt of the fron tires and is used to distribute load across the tread. Any misalignment causes uneven loading on the tires which results in tire wear on one edge.

The most common cause of tire wear on the inside edge is due to the camber misalignment which results in premature tire wear.

Another reason is of tire wear is vehicle’s toe. A slight misalignment of the toe reduces the life of the tire.

Since it is given that camber settings and toe settings are within specification therefore, tire tread wear on the inside edge cannot happen if camber and toe are within specification.

Technician A cannot be right.

Effects of Caster misalignment:

Whenever there is a misalignment of the castor then the vehicle will not be able to go in straight line rather it will pull to either left or right side. Caster misalignment also causes heavy or light steering depending upon the positive or negative misalignment of caster.

Since it is given that caster settings are not within specification therefore, the vehicle may pull to the left due to the caster misalignment.

Technician B must be right.

4 0
4 years ago
If the feedforward path of a control system contains at least one integrating element, then the output continues to change as lo
Thepotemich [5.8K]

Answer:

The attached system shows that there’s an integrator between the point where disturbance enters the system and error measuring element. A any time when R(s)=0 then

\frac {C(s)}{D(s)}=\frac {G(s)}{1+G_c(s)G(s)} and considering that E(s)=D(s)-G_c(s)C(s) then

\frac {E(s)}{D(s)}=1-(\frac {C(s)}{D(s)})G_c(s)

\frac {E(s)}{D(s)}=1-(\frac {G(s)}{1+G_c(s)D(s)})G_c(s)

\frac {E(s)}{D(s)}=\frac {1}{1+G_c(s)G(s)}

E(s)=\frac {D(s)}{1+G_c(s)G(s)}

For ramp disturbance d(t)=at

D(s)=\frac {a}{s^{2}} therefore, the steady state error is given by

e(\infty)= \lim_{s \to 0} s E(s)

e(\infty)= \lim_{s \to 0} s [\frac {D(s)}{1+G_c(s)G(s)}]

e(\infty)= \lim_{s \to 0} s [\frac {a}{s^{2}+s^{2}G_c(s)G(s)}]

e(\infty)= \lim_{s \to 0} s [\frac {a}{s+sG_c(s)G(s)}]

e(\infty)= \lim_{s \to 0} s [\frac {a}{sG_c(s)G(s)}]

Whenever G_c(s) has a double intergrator, the error e(\infty) becomes zero

3 0
3 years ago
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