7. The "3 second rule" is the time you should pause at an intersection marked with a stop sign.

A small family home in Tucson, Arizona has a rooftop area of 2667 square feet, and it is possible to capture rain falling on abo

Kazeer [188]

Answer:

volume = 53.747 m3 = 14198.138 gal

weight = 526652 N = 118396.08 lbf

Explanation:

We know that volume of water

$volume = A'\times H$

where A' = 61% of A

$= 0.61\times 2667 = 1626.87 sq ft$

$volume = 1626.87 \times (\frac{14}{12} ft)$

=1898.015 ft^3

$in\ m^3 = \frac{ 1898.015}{35.315} = 53.7457 m^3$

$in\ gallon = 1898.015 \times 7.481 = 14198.138 gallon$

$weight = \rho Vg$

$= 1000\times 53.74\times 9.8$

=526652 N

$In\ lbf = \frac{526652}{4.448} = 118396.08 lbf$

7 0

3 years ago

In C++ the declaration of floating point variables starts with the type name float or double, followed by the name of the variab

Aliun [14]

Answer:

The given grammar is :

S = T V ;

V = C X

X = , V | ε

T = float | double

C = z | w

1.

Nullable variables are the variables which generate ε ( epsilon ) after one or more steps.

From the given grammar,

Nullable variable is X as it generates ε ( epsilon ) in the production rule : X -> ε.

No other variables generate variable X or ε.

So, only variable X is nullable.

2.

First of nullable variable X is First (X ) = , and ε (epsilon).

L.H.S.

The first of other varibles are :

First (S) = {float, double }

First (T) = {float, double }

First (V) = {z, w}

First (C) = {z, w}

R.H.S.

First (T V ; ) = {float, double }

First ( C X ) = {z, w}

First (, V) = ,

First ( ε ) = ε

First (float) = float

First (double) = double

First (z) = z

First (w) = w

Explanation:

7 0

3 years ago

Match the terms with the correct definitions.

arsen [322]

I think answer should be the first one please give me brainlest let me know if it’s correct or not okay thanks bye

7 0

2 years ago

What is the probability that Tina will NOT wear a white t-shirt on the first day of her trip?

katrin2010 [14]

Answer:

4/5

Explanation:

She is not wearing white t-shirt on the first day so she is wearing the other 4 t-shirt

4 0

3 years ago

In part A you are asked to write the pseudocode for the program. In part B you are asked to write the syntax of the code for the

Naya [18.7K]

Answer:

C++.

Explanation:

#include <iostream>

#include <string>

using namespace std;

///////////////////////////////////////////////////////////////

int main() {

string quote, book;

int page;

cout<<"What is your favorite quote from a book?"<<endl;

getline(cin, quote);

cout<<endl;

/////////////////////////////////////////////

cout<<"What book was that quote from?"<<endl;

getline(cin, book);

cout<<endl;

/////////////////////////////////////////////

cout<<"What page was that quote from?"<<endl;

cin>>page;

cout<<endl;

/////////////////////////////////////////////

int no_of_upper_characters = 0;

for (int i=0; i<quote.length(); i++) {

if (isupper(quote[i]))

no_of_upper_characters++;

}

cout<<"No. of upper case characters: "<<no_of_upper_characters<<endl;

/////////////////////////////////////////////

int no_of_characters = quote.length();

cout<<"No. of characters: "<<no_of_characters<<endl;

/////////////////////////////////////////////

bool isDog = false;

for (int i=0; i<quote.length(); i++) {

if (isDog == true)

break;

else if (quote[i] == 'd') {

for (int j=i+1; j<quote.length(); j++) {

if (isDog == true)

break;

else if (quote[j] == 'o') {

for (int z=j+1; z<quote.length(); z++) {

if (quote[z] == 'g') {

isDog = true;

break;

}

if (isDog == true)

cout<<"This includes 'd' 'o' 'g' in the quote";

//////////////////////////////////////////////

return 0;

}

3 0

3 years ago