Answer:
-50.005 KJ
Explanation:
Mass flow rate = 0.147 KJ per kg
mass= 10 kg
Δh= 50 m
Δv= 15 m/s
W= 10×0.147= 1.47 KJ
Δu= -5 kJ/kg
ΔKE + ΔPE+ ΔU= Q-W
0.5×m×(30^2- 15^2)+ mgΔh+mΔu= Q-W
Q= W+ 0.5×m×(30^2- 15^2) +mgΔh+mΔu
= 1.47 +0.5×1/100×(30^2- 15^2)-9.7×50/1000-50
= 1.47 +3.375-4.8450-50
Q=-50.005 KJ
The answer is Both A and C. It is also known as glass lining and vitreous enamel.
Explanation:
Porcelain enamel is sometimes referred to as glass lining and vitreous enamel. It is a thin layer of ceramic or glass applied to a substrate of metal, which is used to protect surfaces from chemical attack and physical damage.
They can modify the structural characteristics of the substrate and improve the appearance of the product.
Porcelain enamel coating is used in applications like smooth, very durable, scratch and chemical resistant coating is needed. Industrial porcelain enamel is also known as glass lining are used in industrial rather than artistic and applications.
Explanation:
The Release Train Engineer (RTE) has the main work of supporting as well as coaching the Agile Release Train (ART). They are capable of steering ART successfully and to navigate the complexity in delivering the software in large and inter-functional environments.
They serve the scrum master and coach teams to improve on the results.
The two actions or behaviors of the RTE are :
1. They try to create an environment of the mutual influence.
2. Listens and also supports the teams in problem identification as well as decision-making.
Answer with Explanation:
The capillary rise in 2 parallel plates immersed in a liquid is given by the formula

where
is the surface tension of the liquid
is the contact angle of the liquid
is density of liquid
'g' is acceleratioj due to gravity
'd' is seperation between thje plates
Part a) When the liquid is water:
For water and glass we have
Applying the values we get

Part b) When the liquid is mercury:
For mercury and glass we have
Applying the values we get

The negative sign indicates that there is depression in mercury in the tube.
Answer:
Q= 4.6 × 10⁻³ m³/s
actual velocity will be equal to 8.39 m/s
Explanation:
density of fluid = 900 kg/m³
d₁ = 0.025 m
d₂ = 0.05 m
Δ P = -40 k N/m²
C v = 0.89
using energy equation

under ideal condition v₁² = 0
v₂² = 88.88
v₂ = 9.43 m/s
hence discharge at downstream will be
Q = Av
Q =
Q =
Q= 4.6 × 10⁻³ m³/s
we know that

hence , actual velocity will be equal to 8.39 m/s