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irina [24]
3 years ago
7

Explain why the second is not defined by the length of the day.

Chemistry
2 answers:
Gekata [30.6K]3 years ago
4 0
Because a second passes fo fast.
olga2289 [7]3 years ago
3 0
The day's length is not a settled unit of time.

The earth itself is jiggling around space, going on an amazingly slight bended way and the unrest is dialing down record of tidal movement and the moon moving possibly away.
The day's length changes amid the time and in addition about predictably or something to that effect, and extra hop second is added to the timetable.
The second is portrayed using different unrests of the cesium 133 particle at 0 Kelvin in light of the fact that isolated from quantum mechanics, it isn't at risk to coincidental segments.


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List the four groups attached to the central carbon of an amino acid.
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Read 2 more answers
1. Find the masses of the following amounts.
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The mass of 2.15 mol of hydrogen sulphide (H₂S) will be 73.272 gm and the mass of  3.95 × 10⁻³ mol of lead(II) iodide, (PbI₂) will be 1.82 gm

<h3>What is Mole ?</h3>

A mole is a very important unit of measurement that chemists use.

A mole of something means you have 6.023 x 10 ²³ of that thing.

  • For 2.15 mol of hydrogen sulphide (H₂S) :

1 mole hydrogen sulphide (H₂S) = 34.08088 grams

Therefore,

2.15 mol of hydrogen sulphide (H₂S) = 34.08088 grams x 2.15 mol

                                                              = 73.272 gm

  • For 3.95 × 10⁻³ mol of lead(II) iodide, (PbI₂) ;

1 mol of lead(II) iodide, (PbI₂) = 461.00894 grams

Therefore,

3.95 × 10⁻³ mol of lead(II) iodide, (PbI₂) = 461.00894 grams x 3.95 × 10⁻³ mol

                                                                  = 1.82 gm

Hence,The mass of 2.15 mol of hydrogen sulphide (H₂S) will be 73.272 gm and the mass of  3.95 × 10⁻³ mol of lead(II) iodide, (PbI₂) will be 1.82 gm

Learn more about mole here ;

brainly.com/question/21323029

#SPJ1

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Determine an empirical formula from each set of
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59.30% I

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mi respuesta es esa porque es la más sercana

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Hi, I am Rosy67 and im here to help.

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