Taking into account the reaction stoichiometry, 2 moles of CaO are required to react with 2 moles of Ca(OH)₂.
<h3>Reaction stoichiometry</h3>
In first place, the balanced reaction is:
CaO + H₂O → Ca(OH)₂
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:
- CaO: 1 mole
- H₂O: 1 mole
- Ca(OH)₂: 1 mole
<h3>Moles of CaO required</h3>
The following rule of three can be applied: If by stoichiometric reaction 1 mole of Ca(OH)₂ is produced by 1 mole of CaO, 2 moles of Ca(OH)₂ are produced by how many moles of CaO?

moles of CaO= 2 moles
Finally, 2 moles of CaO are required to react with 2 moles of Ca(OH)₂.
Learn more about the reaction stoichiometry:
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5.18mL i hope this helps i hope this does to!
Answer:
195.199grams
Explanation:
Fluorine has a molar mass of 18.99984 while calcium has a molar mass of calcium is 40.08.
1 mole of calcium fluoride has a mass of 40.08+2×18.99984
=78.0797 grams
if one mole has a mass of 78.0797 grams, then 2.5 moles have:
2.5 moles× 78.0797 grams/mole= 195.1992 grams
0.01 cubic meters
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