Answer:
D
Explanation:
I think but it is an better attempt than the other guy answer.
Answer:
C) LiOH + HCl → LiCl + H₂O
General Formulas and Concepts:
<u>Chemistry - Reactions</u>
- Synthesis Reactions: A + B → AB
- Decomposition Reactions: AB → A + B
- Single-Replacement Reactions: A + BC → AB + C
- Double-Replacement Reactions: AB + CD → AD + BC
Explanation:
<u>Step 1: Define</u>
RxN A: 2Na + 2H₂O → 2NaOH + H₂
RxN B: CaCO₃ → CaO + CO₂
RxN C: LiOH + HCl → LiCl + H₂O
RxN D: CH₄ + 2O₂ → CO₂ + 2H₂O
<u>Step 2: Identify</u>
RxN A: Single Replacement Reaction
RxN B: Decomposition Reaction
RxN C: Double Replacement Reaction
RxN D: Combustion Reaction
I think it is trace evidence since it is really small and hard to find.
Answer:
= 9.28 g CO₂
Explanation:
First write a balanced equation:
CH₄ + 2O₂ -> 2H₂O + CO₂
Convert the information to moles
7.50g CH₄ = 0.46875 mol CH₄
13.5g O₂ = 0.421875 mol O₂
Theoretical molar ratio CH₄:O₂ -> 1:2
Actual ratio is 0.46875 : 0.421875 ≈ 1:1
If all CH₄ is used up, there would need to be more O₂
So O₂ is the limiting reactant and we use this in our equation
Use molar ratio to find moles of CO₂
0.421875 mol O₂ * 1 mol CO₂/2 mol O₂=0.2109375 mol CO₂
Then convert to grams
0.2109375 mol CO₂ = 9.28114 g CO₂
round to 3 sig figs
= 9.28 g CO₂
Pretty sure it is 128 hope this helps you :D
