Answer:
The rate of the reaction will increase by a factor of 9.
Explanation:
Hello,
In this case, considering the given second-order reaction, whose rate law results:
![r=k[A] [B]^2](https://tex.z-dn.net/?f=r%3Dk%5BA%5D%20%5BB%5D%5E2)
We easily infer that at constant concentration of A but tripling the concentration of B, we are going to obtain the following increasing factor while holding the remaining variables constant:
![Increase\ factor=\frac{r_{final}}{r_{initial}} =\frac{k[A][3*B]^2}{k[A][B]^2} =\frac{3^2}{1} \\Increase\ factor=9](https://tex.z-dn.net/?f=Increase%5C%20factor%3D%5Cfrac%7Br_%7Bfinal%7D%7D%7Br_%7Binitial%7D%7D%20%3D%5Cfrac%7Bk%5BA%5D%5B3%2AB%5D%5E2%7D%7Bk%5BA%5D%5BB%5D%5E2%7D%20%3D%5Cfrac%7B3%5E2%7D%7B1%7D%20%5C%5CIncrease%5C%20factor%3D9)
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(2) 2 - 7 - 18 - 7 does, because the electron from the L shell jumped to the N shell, which requires energy.
The rest of them are either different types of atoms (different elements) or are not the excited state (ground state)
The greatest aqueous freezing point is (D) 0.10 KCI
Answer:
P_2 =0.51 atm
Explanation:
Given that:
Volume (V1) = 2.50 L
Temperature (T1) = 298 K
Volume (V2) = 4.50 L
at standard temperature and pressure;
Pressure (P1) = 1 atm
Temperature (T2) = 273 K
Pressure P2 = ??
Using combined gas law:




Answer:

Explanation:
Hello there!
In this case, it is possible to comprehend these mass-particles problems by means of the concept of mole, molar mass and the Avogadro's number because one mole of any substance has 6.022x10²³ particles and have a mass equal to the molar mass.
In such a way, for C₆H₁₂O₆, whose molar mass is about 180.16 g/mol, the referred mass would be:

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