Question

A wire carries a current of 0.86 A. This wire makes an angle of 70° with respect to a magnetic field of magnitude 5.8 × 10-5 T. The wire experiences a magnetic force of magnitude 8.5 × 10-5 N. What is the length of the wire?

Answer 1

Answer:

The length of wire is 4.68 m

Explanation:

From the question

Current in wire ; I = 0.86 A

Angle ;$\theta = 70^{o}$

Magnetic Field ; $B = 5.8 \times 10^{-5} T$

Magnetic force ; $F = 8.5 \times 10^{-5} N$

Let length of wire be L,

Now , the formula for force is

$F = I \times B \times L \times sin(\theta)$

rearranged as

$L = \frac{F}{B \times I \times sin(\theta)}$

Insert the values

$L = \frac{8.5 \times 10^{-5}N}{5.8 \times 10^{-5}T \times 0.86 A \times sin(70^{o})}$

$L = 4.68 m$

So the length of wire is 4.68 m