Answer:

Explanation:
Here we know that for the given system of charge we have no loss of energy as there is no friction force on it
So we will have


now we know when particle will reach the closest distance then due to electrostatic repulsion the speed will become zero.
So we have



so distance moved by the particle is given as



From the law of conservation of momentum
m1u1+ m2u2= m1v1+ m2v2
110*8+ 110*-10= 110*-10 + 110* v2
v2= 8 m/sec
Answer:
F = ⅔ F₀
Explanation:
For this exercise we use Coulomb's law
F = k q₁q₂ / r²
let's use the subscript "o" for the initial conditions
F₀ = k q² / r²
now the charge changes q₁ = q₂ = 2q and the new distance is r = 3 r
we substitute
F = k 4q² / 9 r²
F = k q² r² 4/9
F = ⅔ F₀
Answer:
D. 24 lb
Explanation:
Tina has been dieting for 13 weeks
First week she lost 3 pounds
Next week she gained 1 pound and did not lose any. This will be subtracted as she has gained a pound
The remaining 11 weeks she lost 2 pounds per week
Weight lost in the 11 weeks = 11×2 =22 pounds
Total weight lost
3-1+22 = 24 lb
Tina has lost 24 pounds in total during the 13 weeks
a) uniform velocity
b) zero or no acceleration
c) (see picture)
EXPLANATION:
(see picture)