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hichkok12 [17]
3 years ago
13

Describe fractional distillation and explain what a fraction is?

Chemistry
1 answer:
kakasveta [241]3 years ago
5 0

Answer: In a fractional distillation, a mixture of liquids is boiled and the resulting vapors travel up a glass tube called a “fractionating column” and separate. The fractionating column is placed between the flask containing the mixture and the “Y” adaptor and improves the separation between the liquids being distilled.

Explanation:

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Which has a different number of neutrons from protons​
MA_775_DIABLO [31]
I’m not sure but it has to be hydrogen
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4 years ago
What is kinetic energy of a 100 kg object that is moving with a speed of 15 m/s
elena-s [515]

Answer:

16875 Joules

Kg m^2 s^-2 = Joule ,so The kinetic energy of a body of mass 150 Kg moving at 15m/s is 16875 Joules.

Explanation:

6 0
3 years ago
For the reaction N2(g) + O2(g)2NO(g) H° = 181 kJ and S° = 24.9 J/K G° would be negative at temperatures (above, below) K. Enter
12345 [234]

ΔG deg will be negative above 7.27e+3 K.

<u>Explanation:</u>

  • The ΔG deg with the temperature can be found using the formula and the formula is given below
  • ΔG deg = ΔH deg - T ΔS deg
  • Given data, ΔH deg = 181kJ and ΔSdeg=24.9J/K
  • -T ΔS deg will be always negative and ΔG deg = ΔH deg  will  be  positive and ΔG deg will be negative at relatively high temperatures and positive at relatively low temperatures
  • solving the equation and substitute  ΔGdeg=0
  • ΔGdeg = ΔHdeg - T ΔSdeg
  • T= ΔHdeg/ΔSdeg
  • T=181 kJ / 2.49e-2 kJK-1
  • By simplification we get
  • T=7.27 × 10^3 K.
  • Therefore, Go will be negative above   7.27 × 10^3 K
  • Since ΔG deg = -RT lnK, when ΔGdeg < 0, K > 1 so the reaction will have K > 1 above 7.27 × 10^3 K.
  • ΔG deg will be negative above 7.27e+3 K.

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7 0
3 years ago
The fragrant organic compounds found in many flowers that contain a carbonyl group bonded to a carbon atom and a hydrogen atom a
Mandarinka [93]
The fragrant organic compounds found in many flowers that contain a carbonyl group bonded to a carbon atom and a hydrogen atom are called aldehydes.
4 0
3 years ago
Read 2 more answers
Determine the specific heat (in J/g C) for a 2.508 kilogram substance which increases its temperature from 4.051 C to 42.061 C w
just olya [345]

Answer: 0.036 J/g°C

Explanation:

The quantity of heat energy (Q) required to raise the temperature of a substance depends on its Mass (M), specific heat capacity (C) and change in temperature (Φ)

Thus, Q = MCΦ

Given that,

Q = 3.42 Kilojoules

[Convert 3.42 kilojoules to joules

If 1 kilojoule = 1000 joules

3.42 kilojoules = 3.42 x 1000 = 3420J]

Mass = 2.508Kg

[Convert 2.508 kg to grams

If 1 kg = 1000 grams

2.508kg = 2.508 x 1000 = 2508g]

C = ? (let unknown value be Z)

Φ = (Final temperature - Initial temperature)

= 42.061°C - 4.051°C

= 38.01°C

Apply the formula, Q = MCΦ

3420J = 2508g x Z x 38.01°C

3420J = 95329.08g•°C x Z

Z = (3420J / 95329.08g•°C)

Z = 0.03588 J/g°C

Round the value of Z to the nearest thousandth, hence Z = 0.036 J/g°C

Thus, the specific heat of the substance is 0.036 J/g°C

7 0
3 years ago
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