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3 years ago

Write a scientific argument that addresses the question: Why is Jackie an elite distance runner when no one else

Chemistry

1 answer:

Travka [436]3 years ago

7 0

Answer:

A mutation in Jackie's genes culminated in developing a new enzyme, resulting in the long-distance running phenotype. Jackie appears to have either the A1Am or A2Am gene variants. Jackie used to play for long periods without tiring, suggesting that her gene variants could generate a protein that results in a stamina feature. Jackie's father bears the A1A2 gene. Since Jackie's mother is a good sprinter, I suspect she bears A1A1 gene variants. Sprinters have much ACTN3 protein in their cells, so that she may have two copies of the A1 gene variant. This means Jackie has at least one clone of the A1 gene allele. People with one or two versions of the A1 gene variant, on the other hand, are rarely successful long-distance runners. Out of 100 total distance runners, only 28 (25 and 3) have an A1 gene copy. Since the gene variants she may have inherited from her parents cannot justify her stamina, she may have a mutant gene version that contains a long-distance running protein. However, I do not believe she has AmAm gene versions because mutations are uncommon. Jackie is an elite long-distance runner due to a gene that no one else in her family has.

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3 years ago

If a system has a reaction quotient of 2.13 ✕ 10−15 at 100°C, what will happen to the concentrations of COBr2, CO, and Br2 as th

qaws [65]

This is an incomplete question, here is a complete question.

Consider the following equilibrium at 100°C.

$COBr_2(g)\rightleftharpoons CO(g)+Br_2(g)$

$K_c=4.74\times 10^4$

Concentration at equilibrium:

$[COBr_2]=1.58\times 10^{-6}M$

$[Co]=2.78\times 10^{-3}M$

$[Br_2]=2.51\times 10^{-5}M$

If a system has a reaction quotient of 2.13 × 10⁻¹⁵ at 100°c, what will happen to the concentrations of COBr₂, Co and Br₂ as the reaction proceeds to equilibrium?

Answer : The concentrations of Co and Br₂ decreases and the concentrations of COBr₂ increases.

Explanation :

Reaction quotient (Q) : It is defined as the measurement of the relative amounts of products and reactants present during a reaction at a particular time.

The given balanced chemical reaction is,

$COBr_2(g)\rightleftharpoons CO(g)+Br_2(g)$

The expression for reaction quotient will be :

$Q=\frac{[CO][Br_2]}{[COBr_2]}$

In this expression, only gaseous or aqueous states are includes and pure liquid or solid states are omitted.

Now put all the given values in this expression, we get

$Q=\frac{(2.78\times 10^{-3})\times (2.51\times 10^{-5})}{(1.58\times 10^{-6})}=4.42\times 10^{-2}$

The given equilibrium constant value is, $K_c=4.74\times 10^4$

Equilibrium constant : It is defined as the equilibrium constant. It is defined as the ratio of concentration of products to the concentration of reactants.

There are 3 conditions:

When $Q>K_c$ that means product > reactant. So, the reaction is reactant favored.

When $Q$ that means reactant > product. So, the reaction is product favored.

When $Q=K_c$ that means product = reactant. So, the reaction is in equilibrium.

From the above we conclude that, the $Q$ that means product < reactant. So, the reaction is product favored that means reaction must shift to the product (right) to be in equilibrium.

Hence, the concentrations of Co and Br₂ decreases and the concentrations of COBr₂ increases.

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3 years ago

fish give off the compound ammonia which has a pH above 7 to which class of compounds does ammonia belong

jasenka [17]

Answer:
The compound ammonia given by fish is alkaline

Explanation:
We can classify elements/compounds based on their pH values into three types:
acids: these are compounds having pH value lower than 7
neutral: these are compounds having pH value equal to 7
alkalies: these are compounds having pH values higher than 7

This is shown in the attached image

We are given that the pH of the compound ammonia generated by the fish is above 7.
According to the above explanation, compound ammonia would be an alkaline compound.

Hope this helps :)

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3 years ago