Nuclear reaction: ¹¹C → ¹¹B + e⁺(positron) + ve(electron neutrino).<span><span><span><span>
</span></span></span></span>Beta
decay is radioactive decay<span> in which
a beta ray and a neutrino are emitted from an atomic
nucleus.
There are two types of beta
decay: beta minus and beta
plus. In beta minus decay, neutron is converted to a
proton and an electron and
an electron antineutrino and in beta
plus decay, a proton is converted to a neutron and positron and an electron neutrino, so mass number does not change.</span>
I don't see the options for an answer, so here is a list of all of the transition metals lol
- <em>Scandium</em>
- <em>Titanium</em>
- <em>Vanadium</em>
- <em>Chromium</em>
- <em>Manganese</em>
- <em>Iron</em>
- <em>Cobalt</em>
- <em>Nickel</em>
- <em>Copper</em>
- <em>Zinc</em>
- <em>Yttrium</em>
- <em>Zirconium</em>
- <em>Niobium</em>
- <em>Molybdenum</em>
- <em>Technetium</em>
- <em>Ruthenium</em>
- <em>Rhodium</em>
- <em>Palladium</em>
- <em>Silver</em>
- <em>Cadmium</em>
- <em>Lanthanum</em>
- <em>Hafnium</em>
- <em>Tantalum</em>
- <em>Tungsten</em>
- <em>Rhenium</em>
- <em>Osmium</em>
- <em>Iridium</em>
- <em>Platinum</em>
- <em>Gold</em>
- <em>Mercury</em>
- <em>Actinium</em>
- <em>Rutherfordium</em>
- <em>Dubnium</em>
- <em>Seaborgium</em>
- <em>Bohrium</em>
- <em>Hassium</em>
- <em>Meitnerium</em>
- <em>Darmstadtium</em>
- <em>Roentgenium</em>
- <em>Copernicium p</em>
Answer:
The graph of this equation is shown in Figure 1. As you can see this is a straight line with negative slope and does not intersect the y-axis. So the ...
Explanation:
+5
Explanation:
The given radical is PO₄³⁻
To solve this problem, we need to understand what oxidation number entails.
The extent of the oxidation of each atom is expressed by the oxidation number.
Here are some rules for assigning them:
- Elements in an uncombined state or elements that combines with one another, their oxidation number is zero.
- The charge on an ion is its oxidation number
- In an neutral compound, algebraic sum of all the oxidation numbers of all atoms is zero.
- In a radical, the algebraic sum of all the oxidation numbers of the ions is equal to the charge on them.
Oxygen is known to have an oxidation number of -2;
PO₄³⁻
P + 4(-2) = -3
P -8 = -3
P = -3 + 8 = +5
The charge on phosphorus is +5
learn more:
Oxidation number brainly.com/question/2086855
#learnwithbrainly
Answer:
The amount of NaOH required to prepare a solution of 2.5N NaOH.
The molecular mass of NaOH is 40.0g/mol.
Explanation:
Since,
NaOH has only one replaceable -OH group.
So, its acidity is one.
Hence,
The molecular mass of NaOH =its equivalent mass
Normality formula can be written as:
Substitute the given values in this formula to get the mass of NaOH required.

Hence, the mass of NaOH required to prepare 2.5N and 1L. solution is 100g